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jeyben [28]
3 years ago
13

Calculate the momentum pelephant of a 2140 kg elephant charging a hunter at a speed of 7.63 m/s . pelephant= kg⋅m/s Compare the

elephant's momentum with the momentum pdart of a 0.0415 kg tranquilizer dart fired at a speed of 619 m/s . pelephant=pdart pelephant>pdart More information is needed to determine how the momentums compare. pelephant
Physics
1 answer:
Zepler [3.9K]3 years ago
7 0

Answer:

Momentum of elephant is greater than momentum of tranquilizer dart

Explanation:

m_e = Mass of elephant = 2140 kg

m_d = Mass of tranquilizer dart = 0.0415 kg

v_e = Velocity of elephant = 7.63 m/s

v_e = Velocity of tranquilizer dart = 619 m/s

Momentum of elephant

p_e=m_ev_e\\\Rightarrow p_e=2140\times 7.63\\\Rightarrow p_e=16328.2\ N.s

Momentum of tranquilizer dart

p_d=m_dv_d\\\Rightarrow p_d=0.0415\times 619\\\Rightarrow p_d=25.6885\ N.s

So, p_e>p_d

Momentum of elephant is greater than momentum of tranquilizer dart

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Newton’s second law of motion addresses the relationship between what two variables that influence the force on a body?
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Explanation:

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Define pressure snd state its SI units to​
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A uranium and iron atom reside a distance R = 44.10 nm apart. The uranium atom is singly ionized; the iron atom is doubly ionize
Ad libitum [116K]

Answer:

distance r from the uranium atom is 18.27 nm

Explanation:

given data

uranium and iron atom distance R = 44.10 nm

uranium atom = singly ionized

iron atom = doubly ionized

to find out

distance r from the uranium atom

solution

we consider here that uranium electron at distance = r

and electron between uranium and iron so here

so we can say electron and iron  distance = ( 44.10 - r ) nm

and we know single ionized uranium charge q2= 1.602 × 10^{-19} C

and charge on iron will be q3 = 2 × 1.602 × 10^{-19} C

so charge on electron is q1 =  - 1.602 × 10^{-19} C

and we know F = k\frac{q*q}{r^{2} }  

so now by equilibrium

Fu = Fi

k\frac{q*q}{r^{2} }  =  k\frac{q*q}{r^{2} }

put here k = 9*10^{9} and find r

9*10^{9}\frac{1.602 *10^{-19}*1.602 *10^{-19}}{r^{2} }  =  9*10^{9}\frac{1.602 *10^{-19}*1.602 *10^{-19}}{(44.10-r)^{2} }

\frac{1}{r^{2} } = \frac{2}{(44.10 -r)^2}

r = 18.27 nm

distance r from the uranium atom is 18.27 nm

6 0
3 years ago
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