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RideAnS [48]
3 years ago
5

Ayuda por favor necesito entregar el trabajo y no tengo tiempo

Physics
1 answer:
Sloan [31]3 years ago
5 0
Hola trabajor uno does cuarto
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what would happen to the simple circuit if an additional wire were added to the circuit to connect the terminals of the bulb to
lilavasa [31]

As current increases, the wires heat which can cause a fuse to blow or a circuit breaker to trip. As additional branches are added to a parallel circuit, the overall resistance of the circuit decreases. A decrease in resistance creates an increase in current.

<h3>What is a Simple circuit ?</h3>

A battery (or other energy source), a light bulb (or other energy-consuming device), and conducting wires that connect the two terminals of the battery to the two ends of the light bulb make up a simple electric circuit.

  • Three elements make up an electric circuit: a power source, such as a battery or the mains. a lightbulb-like energy receiver an energy conduit, such as a wire

Learn more about Simple circuit here:

brainly.com/question/530349

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6 0
2 years ago
mechanical (sound) waves are unable to travel through a vacuum such as through space but radio waves are transmitted to earth fr
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Answer: radio waves dont need a medium to travel through

Explanation:

4 0
3 years ago
Becky has a shower and uses 20,000g of water with a specific heat capacity of 4200J/KG. When the water is supplied with 336,000J
lara [203]

Answer:

46°C

Explanation:

q = mCΔT

336,000 J = (20 kg) (4200 J/kg/°C) (50°C − T)

T = 46°C

7 0
3 years ago
Which of the following is the correctly abbreviated SI unit describing the mass of an object
frosja888 [35]
Mass is Kg 
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8 0
3 years ago
Read 2 more answers
3. The circuit below shows two outdoor lights, run by a battery. Four amps of
miv72 [106K]

Answer:

The answer to your question is given below.

Explanation:

From the diagram given in the question, we can see that the bulbs are in parallel connection. This implies that different current will go through the bulb but the same voltage. But the resistance of each bulb is the same, therefore the same current current will go through them.

This can further be understood if we determine the current flowing through each bulb. This is illustrated below:

Voltage (V) = 30V

Resistant 1 (R1) = 15Ω

Current 1 (I1) =..?

V = I1R1

30 = I1 x 15

Divide both side by 15

I1 = 30/15

I1 = 2A.

Voltage (V) = 30V

Resistant 2 (R2) = 15Ω

Current 2 (I2) =..?

V = I2R2

30 = I2 x 15

Divide both side by 15

I2 = 30/15

I2 = 2A.

The overall current(I) in the circuit:

I = I1 + I2

I = 2 + 2 = 4A.

From the illustrations above, we can see that the same current will flow through each bulb as the will current split into two equal parts

4 0
4 years ago
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