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2 years ago

5

Becky has a shower and uses 20,000g of water with a specific heat capacity of 4200J/KG. When the water is supplied with 336,000J

of energy, it heats up to 50^c. What is the startig temperature of the water?

1 answer:

lara [203]2 years ago

7 0

Answer:

46°C

Explanation:

q = mCΔT

336,000 J = (20 kg) (4200 J/kg/°C) (50°C − T)

T = 46°C

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Answer:

Part a)

V = 18.16 V

Part b)

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Part c)

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Part d)

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Part e)

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Explanation:

Part a)

When battery is in charging mode

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here we have

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$\Delta V = 12 + (0.11)(56) = 18.16 V$

Part b)

Rate of energy dissipation inside the battery is the energy across internal resistance

so it is given as

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Part c)

Rate of energy conversion into EMF is given as

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Part d)

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Part e)

now the rate of energy dissipation is given as

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