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2 years ago

When you power an electromagnet with 3 batteries, what variable decreases as a result of removing one of those batteries.

Physics

1 answer:

Snezhnost [94]2 years ago

3 0

Answer:

The strength of the magnetic field decreases as a result of removing one of those batteries.

Hope this helps!

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the dimensions of a cuboidal block are 2.5 m * 2m * 1.2m its weight 900 n what is the minimum presseure exerted by the block on

aleksandr82 [10.1K]

Answer:

your answer is here 180

Explanation:

900/2.5 * 2 = 180

6 0

1 year ago

Read 2 more answers

The radius k of the equivalent hoop is called the radius of gyration of the given body. Using this formula, find the radius of g

Morgarella [4.7K]

Here is the full question:

The rotational inertia I of any given body of mass M about any given axis is equal to the rotational inertia of an equivalent hoop about that axis, if the hoop has the same mass M and a radius k given by:

$k=\sqrt{\frac{I}{M} }$

The radius k of the equivalent hoop is called the radius of gyration of the given body. Using this formula, find the radius of gyration of (a) a cylinder of radius 1.20 m, (b) a thin spherical shell of radius 1.20 m, and (c) a solid sphere of radius 1.20 m, all rotating about their central axes.

Answer:

a) 0.85 m

b) 0.98 m

c) 0.76 m

Explanation:

Given that: the radius of gyration $k=\sqrt{\frac{I}{M} }$

So, moment of rotational inertia (I) of a cylinder about it axis = $\frac{MR^2}{2}$

$k=\sqrt{\frac{\frac{MR^2}{2}}{M} }$

$k=\sqrt{{\frac{MR^2}{2}}* \frac{1}{M} }$

$k=\sqrt{{\frac{R^2}{2}}$

$k={\frac{R}{\sqrt{2}}$

$k={\frac{1.20m}{\sqrt{2}}$

k = 0.8455 m

k ≅ 0.85 m

For the spherical shell of radius

(I) = $\frac{2}{3}MR^2$

$k = \sqrt{\frac{\frac{2}{3}MR^2}{M} }$

$k = \sqrt{\frac{2}{3} R^2}$

$k = \sqrt{\frac{2}{3} }*R$

$k = \sqrt{\frac{2}{3}} *1.20$

k = 0.9797 m

k ≅ 0.98 m

For the solid sphere of radius

(I) = $\frac{2}{5}MR^2$

$k = \sqrt{\frac{\frac{2}{5}MR^2}{M} }$

$k = \sqrt{\frac{2}{5} R^2}$

$k = \sqrt{\frac{2}{5} }*R$

$k = \sqrt{\frac{2}{5}} *1.20$

k = 0.7560

k ≅ 0.76 m

6 0

3 years ago

When the current in a toroidal solenoid is changing at a rate of 0.0260 A/s, the magnitude of the induced emf is 12.6 mV. When t

andrew11 [14]

Answer:

N= 238 turns

Explanation:

The induced Emf that goes through a solenoid can be calculated using the below formula;

Where ξ=induced Emf

L= self inductance

I= current

ξ= L|dⁱ/dt|

Making L which is the self inductance subject of formula we have

L=ξ/[|dⁱ|*|dt|]

The current here is changing at the rate of

.0260 A/s

L=NΦB/i

N=ξ/Φ|di|*|dt|

Magnitude of the induced Emf given= 12.6mV then if we convert to volt we have 12.6×10⁻³ V

The current I = 1.40A

Magnitude flux through the flux=/0.00285 Wb

Then if we substitute all this Value to equation above we have

N=(12.6×10⁻³ V×1.40A)/(0.00285 Wb×0.0260 A/s)

N=238turn

Therefore, there are 238turns in the solenoid

4 0

3 years ago

HELP ME PLEASE!!!THIS IS SCIENCE!!

emmainna [20.7K]

The very first option is correct, as any other answer is either incorrect in terms of optics or does not stop you from seeing the apple.

4 0

3 years ago

PLEASE HELPPP!!! Where do you think our modern ideas about government came from?

Vadim26 [7]

Answer:

Our modern ideas about government were influenced by many different ideas and traditions. The biggest influence came from their British heritage. (Remember the colonists WERE British until the American Revolution!)

7 0

3 years ago