I am thinking the answer is B. I think this because Bohr had a model similar, but his was lacking the cloud of electrons. His just had electrons orbiting the nucleus.
I hope this is right!<span />
Answer:
B.
Explanation:
Elemental analysis involves the actual percentage compositions of each element in the sample of the compounds. We know that there are two different compounds here that both contain copper and oxygen. What we don't know is the actual number of copper or oxygen composed in the compounds.
An elemental composition of these compounds would thus tell us this and will give an idea of the chemical formula of each since we now know quite well the percentage composition of each of these elements
Answer:
Fe is limiting reactant and 3.00g of Fe2O3 will be produced
Explanation:
To solve this question we must convert the mass of each reactant to moles and, using the reaction we can find limiting reactant. With moles of limiting reactant we can find moles of Fe2O3 and its mass as follows:
<em>Moles Fe -Molar mass: 55.845g/mol-</em>
2.1g * (1mol / 55.845g) = 0.0376 moles
<em>Moles O2 -Molar mass: 32g/mol-</em>
2.1g * (1mol / 32g) = 0.0656 moles
For a complete reaction of 0.0656 moles of O2 are needed:
0.0656moles O2 * (4mol Fe / 3 mol O2) = 0.0875 moles Fe
As there are just 0.0376 moles,
Fe is limiting reactant
The mass of Fe2O3 is:
<em>Moles:</em>
0.0376 moles Fe* (2mol Fe2O3 / 4mol Fe) = 0.0188 moles Fe2O3
<em>Mass:</em>
0.0188 moles Fe2O3 * (159.69g / mol) =
3.00g of Fe2O3 will be produced
