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BaLLatris [955]
3 years ago
10

What is the IUPAC name of the following compound?

Chemistry
1 answer:
vaieri [72.5K]3 years ago
4 0

Answer:

2,2,3-trimethylbutane

Step-by-step explanation:

Here are the rules for naming alkanes.

1. Find the longest continuous chain of carbon atoms.

There is a <em>four-carbon chain</em> (blue).

2. Name the main chain.

The chain has four C atoms, so its base name is <em>butane</em>.

3. Identify and name all the substituents.

There are three CH₃ groups (<em>methyl</em><em>,</em> blue bonds).

4. Number the main chain from the end that gives the lowest possible locants to the substituents.

From the left-hand end, the locants are 2,2,3. From the right-hand end, they are 2,3,3. The first point of difference is the second locant. 2 < 3, so we <em>number from the left</em>.

5. Put the names of the substituents with their locants in alphabetical order in front of the base name with no spaces.

Use numbers to connect numbers and hyphens to connect numbers and letters.

The IUPAC name is 2,2,3-trimethylbutane.

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Magnesium and bromine react to produce magnesium bromide. What is the balanced chemical equation for this reaction?​
tia_tia [17]

Answer:

MgBr2

Explanation:

On the periodic table, Magnesium has 2+ charge and Bromine has -1 charge.

You cross charges and get MgBr2

6 0
3 years ago
En un vaso de precipitado de un litro se coloca exactamente 500 mL de agua destilada a temperatura ambiente y se realizan dos ex
Serga [27]

Answer:

1) La masa del agua a temperatura ambiente es de 500 gramos, 2) La masa del agua cuando se congela es de 500 gramos, 3) La masa de agua que queda después de la evaporación es de 400 gramos, 4) Se ha evaporado 100 gramos de agua.

Explanation:

1) <em>¿Cuál es la masa de agua a temperatura ambiente?</em>

Podemos determinar la masa inicial del agua (m_{o}), medido en gramos, al conocer su densidad (\rho_{w}), medida en gramos por mililitro, y volumen inicial ocupado en el vaso de precipitado (V_{o}), medido en mililitros, a partir de la siguiente expresión:

m_{o} =\rho_{w}\cdot V_{o}

Si sabemos que \rho_{w} = 1\,\frac{g}{mL} y V_{o} = 500\,mL, entonces:

m_{o} = \left(1\,\frac{g}{mL} \right)\cdot (500\,mL)

m_{o} = 500\,g

La masa del agua a temperatura ambiente es de 500 gramos.

2) <em>¿Cuál es la masa de agua cuando se congela?</em>

Puesto que el proceso de congelación no implica transferencia de masa, la masa de agua se conserva al transformarse en hielo. Por tanto, la masa resultante es de 500 gramos.

3) <em>¿Cuál es la masa de agua que queda después de la evaporación?</em>

Durante la evaporación una parte del agua es transferida al aire, entonces podemos calcular la masa final (m_{f}), medido en gramos, de la sustancia al multiplicar el volumen final (V_{f}), medido en mililitros, por la densidad del agua (\rho_{w}), medida en gramos por mililitro,. Es decir,

m_{f} =\rho_{w}\cdot V_{f}

Si sabemos que \rho_{w} = 1\,\frac{g}{mL} y V_{f} = 400\,mL, entonces:

m_{f} = \left(1\,\frac{g}{mL} \right)\cdot (400\,mL)

m_{f} = 400\,g

La masa de agua que queda después de la evaporación es de 400 gramos.

4) <em>¿Qué masa de agua se evaporó? </em>

Determinamos que la masa evaporada de agua (m_{v}), medida en gramos, es igual a la diferencia entre las masas inicial y final, ambas medidas en gramos:

m_{v} =m_{o}-m_{f}

Si m_{o} = 500\,g y m_{f} = 400\,g, entonces tenemos que:

m_{v} = 500\,g -400\,g

m_{v} = 100\,g

Se ha evaporado 100 gramos de agua.

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I think the first blank is "solidity" and second is "object."
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