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snow_tiger [21]
2 years ago
8

Why do you see a flash of lightning before you hear the thunder during a storm?

Chemistry
1 answer:
snow_tiger [21]2 years ago
4 0

Answer:

the speed of light travels much faster than the speed of sound.

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PLEASE HELP HELP HELP
mihalych1998 [28]

11.nicotinamid dinucleotid

12.nicotinamid dinucleotid phosphate

13.nicotinamid dinucleotid phosphate hydrogen

14.adenosine diphosphate

15.adenoside triphosphate

8 0
3 years ago
(hurry pls)Carl plugs in a lamp that has 0.67 of resistance and 8.1 volts running through it. What is the amount of current runn
Mazyrski [523]

Answer:

C)12.09 Ampere

Explanation:

V= IR

Where I= current of the system

R= resistance= 0.67 ohm

V= potential difference=8.1 volts

Substitute the values

8.1= I× 0.67

I= 8.1/0.67

=12.09 Ampere

5 0
3 years ago
Let the ED50 of a recreational drug be defined as the amount required for 50% of a test group to feel high or get a buzz. If the
Anastaziya [24]

Explanation:

1) The ED50 value of ethanol = 470 mg per kg of person body = 470 mg/kg

Mass of person = 70 kg

Amount of ethanol required by person of 70 kg to get buzz:

70 kg\times 470 mg/kg=32,900 mg

A 70 kg party goer need to quickly consume in order to have a 50% chance of getting a buzz is 32,900 mg of ethanol.

Mass of ethanol in beer bottle = 13.9 g

Amount of ethanol required by person of 70 kg to get buzz:

70 kg\times 470 mg/kg=32,900 mg =32.9 g

1 mg = 0.001 mg

Bottles of beer would a 70 kg party goer need to consume:

=\frac{32.9 g}{13.9 g}=2.367\approx 2

Bottles of beer would a 70 kg party goer need to consume a 50% chance of getting a buzz is 2.

2)The LD50 value of ethanol = 4,700 mg per kg of person body = 4,700 mg/kg

Mass of person = 70 kg

Amount of ethanol required by person of 70 kg  to have a 50% chance of dying:

70 kg\times 4,700 mg/kg=329,000 mg

A 70 kg party goer need to quickly consume in order to have a 50% chance of dying is 329,000 mg of ethanol.

Mass of ethanol in Jack Daniels bottle = 356 g

Amount of ethanol required by person of 70 kg  to have a 50% chance of dying:

70 kg\times 4,700 mg/kg=329.000 mg =329 g

1 mg = 0.001 mg

Bottles of Jack Daniels would a 70 kg party goer need to consume to have a 50% chance of dying:

=\frac{329 g}{356 g}=0.923\approx 1

Bottles of  Jack Daniels would a 70 kg party goer need to consume to have a 50% chance of dying is 1.

4 0
3 years ago
How many moles are in 182 grams of BC13?
spayn [35]

Answer:

?

Explanation:

5 0
2 years ago
Which equation represents a neutralization reaction?
sergij07 [2.7K]
A neutralization reaction is in essence a reaction between an acid an a base which usually results in pH neutral compounds being formed (a salt and water).  Therefor the answer would be OPTION A  (<span>base + acid → salt + water)</span>
6 0
3 years ago
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