Answer:
A
Explanation:
it has an arrow symbolizing direction because a vector quantity has both magnitude and direction.
Answer:
1000 g
Explanation:
d = m/v
We are given d: 10g/cm3
and v: 100cm3
Plug them into the equation to get 10 = m/100
Then, cross multiply 10x100 to get mass which is: 1000g
Answer : The excess reactant in the combustion of methane in opem atmosphere is
molecule.
Solution : Given,
Mass of methane = 23 g
Molar mass of methane = 16.04 g/mole
The Net balanced chemical reaction for combustion of methane is,

First we have to calculate the moles of methane.
=
= 1.434 moles
From the above chemical reaction, we conclude that
1 mole of methane react with the 2 moles of oxygen
and 1.434 moles of methane react to give
moles of oxygen
The Moles of oxygen = 2.868 moles
Now we conclude that the moles of oxygen are more than the moles of methane.
Therefore, the excess reactant in the combustion of methane in open atmosphere is
molecule.
Answer:
93%
Explanation:
First write the balanced reaction
C3H8 + 5O2 --> 3CO2 +4H2O
2nd, find the theoretical yield
2L C3H8 (1mol/22.4L) (3 mol CO2/1 molC3H8) (22.4 L/ 1mol) = 6L
3rd, Find percent yield
%yield = (actual / theoretical) x100 = (5.7/6) x 100 = 93%