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timurjin [86]
3 years ago
7

Oof im crying rn like fr im ded

Physics
1 answer:
Aneli [31]3 years ago
3 0

Answer:

no kap

Explanation:

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Light-rail passenger trains that provide transportation within and between cities speed up and slow down with a nearly constant
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Answer:

Final Speed: 26m/s

Explanation:

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3 years ago
Which of the following changes will increase the frequency of an oscillating pendulum?
svlad2 [7]

Answer:

c. an increase in the length of the rope.

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Suppose a rocket launches with an acceleration of 34.0 m/s2 what is the apparent weight of an 85-kg astronaut aboard this rocket
docker41 [41]

Answer:

the apparent weight of the astronaut in the rocket is 3723 N.

Given:

acceleration = 34 \frac{m}{s^{2} }

mass of astronaut = 85 kg

To find:

Apparent weight of the astronaut = ?

Solution:

Total weight of the astronaut in a rocket is given by,

W = w + F

W = apparent weight of the astronaut

w = weight of astronaut on earth surface = mg

F = force acting on the astronaut = ma

W = mg+ma

W = m (g+a)

W = 85 (9.8 + 34)

W = 3723 N

Thus, the apparent weight of the astronaut in the rocket is 3723 N.

7 0
3 years ago
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If the coefficient of kinetic friction between tires and dry pavement is 0.84, what is the shortest distance in which you can st
liberstina [14]

Answer:

The shortest distance in which you can stop the automobile by locking the brakes is 53.64 m

Explanation:

Given;

coefficient of kinetic friction, μ = 0.84

speed of the automobile, u = 29.0 m/s

To determine the  the shortest distance in which you can stop an automobile by locking the brakes, we apply the following equation;

v² = u² + 2ax

where;

v is the final velocity

u is the initial velocity

a is the acceleration

x is the shortest distance

First we determine a;

From Newton's second law of motion

∑F = ma

F is the kinetic friction that opposes the motion of the car

-Fk = ma

but, -Fk = -μN

-μN = ma

-μmg = ma

-μg = a

- 0.8 x 9.8 = a

-7.84 m/s² = a

Now, substitute in the value of a in the equation above

v² = u² + 2ax

when the automobile stops, the final velocity, v = 0

0 = 29² + 2(-7.84)x

0 = 841 - 15.68x

15.68x = 841

x = 841 / 15.68

x = 53.64 m

Thus, the shortest distance in which you can stop the automobile by locking the brakes is 53.64 m

4 0
3 years ago
An example of unprofessional behavior is?
nika2105 [10]
B, gossiping is unproessional
7 0
3 years ago
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