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Klio2033 [76]
2 years ago
10

Hi everyone! :)) How is your day going, let me know!

Chemistry
2 answers:
Masja [62]2 years ago
8 0

Answer:

its doing great!

Explanation:

breainleist plss

Shkiper50 [21]2 years ago
4 0
Vas happenin!!


My day is going okay kinda tired how is your day?
You might be interested in
By what factor would a scuba diver’s lungs expand if she ascended rapidly to the surface from a depth of 125 ft without inhaling
vova2212 [387]

It is found that scuba diver’s can safely ascend up to 52.53 ft without Breathing out.

By what factor would a scuba diver’s lungs expand if she ascended rapidly to the surface from a depth of 125 ft without inhaling or exhaling then

p_{1} =patm+pH_{2} O

p_{1} = 101325+ρgh_{1}

It is given that height is 125ft. Put the value of h in above formula:

h1  =125ft=38.1m

ρ=1.04g/mL=1040kg/m^{3}

g=9.81                                  

p_{1} =101325Pa+388711.44

p_{1}   =490036.44‬Pa                

p_{2} =p atm  =101325Pa

It is known that volume and pressure can be expressed as:

V*P=const.

where, V is volume and P is pressure.

Now,              

V_{1} *p_{1} =V_{2}  *p_{2}

V_{2} /V_{1}=p_{2} /p_{1}

V_{2} /V_{1} =490036.44/101325

V_{2} /V_{1}=4.84

Assume constant temperature

d of seawater = 1.04 g/mL; d of Hg = 13.5 g/mL.

now p_{1} =p atm​+pH_{2} O =490036.44Pa

V*p=const                              

where, V is volume and P is pressure.

Now,              

V_{1} *p_{1} =V_{2}  *p_{2}

V_{2} /V_{1}=p_{2} /p_{1}

V_{2} /V_{1} =490036.44/X

p_{2} =490036.44pa/(V2/V1) =326690.96Pa

p_{2} =patm +pH_{2} O

p_{2} =101325Pa+ρgh_{2}

326690.96Pa=101325Pa+ρgh_{2}

ρgh1  =151987.5-101325=225365.96‬‬Pa

ρ=1,04g/mL=1040kg/m3

g=9.81

h_{2} =225365.96/‬ρ∗g

​h_{2}  =225365.96  / ‬1040∗9.81

h_{2}  =22.09m= 72.47ft

ΔH=H_{1} -H_{2}

=125-72.47

=52.53ft

So she can safely ascend up to 52.53 ft without Breathing out

To know more about Scuba diver here

brainly.com/question/15430942

#SPJ4

6 0
1 year ago
How do you balance this Chemical Equation? <br>C5H12O + O2 = CO2 + H2O​
ICE Princess25 [194]

Answer:

The chemical equation by putting, a 2 on C₅H₁₂O, 15 on O₂, 10 on CO₂ , and 12 on H₂O in the equation;

2C₅H₁₂O + 15O₂ → 10CO₂ + 12H₂O​

Explanation:

  • Chemical equations are balanced by putting coefficients on the reactants and products to ensure the total number of atoms on the left side equal to those on the right side.
  • Balancing chemical equations is done to make chemical equations obey the law of conservation of mass.
  • According to the law of conservation of mass, the mass of the reactants should always be equal to the mass of products.
  • This is done by balancing chemical equations to ensure the total number of atoms on the left side is equal to that on the right side.
  • Therefore, the balanced equation is;

          2C₅H₁₂O + 15O₂ → 10CO₂ + 12H₂O​

3 0
3 years ago
Which best describes the relative positions of protons, neutrons, and electrons in an atom?
Anastaziya [24]
Hello!

The center of an atom is called the nucleus; it is comprised of protons and neutrons, collectively known as nucleons. The electrons float around the nucleus in a cloud.

Answer:
A) Protons and neutrons are in the center of the atom, and electrons move around in the cloud.
6 0
3 years ago
I didn’t mean to click that answer I dropped my phone on the computer.
Yanka [14]

its A plant like protist produce oxygen ...

5 0
3 years ago
What is the mass of 3.35 mol Hg(IO3)2? 1,700 g 1,840 g 1,960 g 2,110 g
vichka [17]

Answer:- 1840 g.

Solution:- We have been given with 3.35 moles of  and asked to calculate it's mass.

To convert the moles to grams we multiply the moles by the molar mass of the compound. Molar mass of the compound is the sum of atomic masses of all the atoms present in it.

molar mass of  = atomic mass of Hg + 2(atomic mass of I) + 6(atomic mass of O)

= 200.59+2(126.90)+6(16.00)

= 200.59+253.80+96.00

= 550.39 gram per mol

Let's multiply the given moles by the molar mass:

3.35mol(\frac{550.39g}{1mol})

= 1843.8 g

Since, there are three sig figs in the given moles of compound, we need to round the calculated my to three sig figs also. So, on rounding off to three sig figs the mass becomes 1840 g.



5 0
3 years ago
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