2 years ago

Find the moles in 245g of lithium bromide

1 answer:

3 0

245gLiBr/86.84(molar mass of LiBr)=2.82128 moles

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Zepler [3.9K]

Answer:

$d=1.78\times 10^{-7}\ Dg/\mu m^3$

Explanation:

Given,

The density of Helium is $1.78\times 10^4\ g/cm^3$

We need to find the density in Dg/μm

We know that,

1 g = 10 dg

1 cm³ = 10¹² μm³

So,

$d=1.78 \times 10^4\ g/cm^3\\\\=1.78 \times 10^4\times \dfrac{10\ dg}{10^{12}\ \mu m^3}\\\\=1.78\times 10^{-7}\ Dg/\mu m^3$

So, the density of Helium is equal to $1.78\times 10^{-7}\ Dg/\mu m^3$ .

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2 years ago