C) 6h i’m not that great at math but that’s what i got hope it helps!!
False, it was Wilhelm Wundt that founded the first formal laboratory for research in psychological studies.
*** B.F Skinner is known for inventing the operant conditioning chamber. ***
Answer:
a) t1 = v0/a0
b) t2 = v0/a0
c) v0^2/a0
Explanation:
A)
How much time does it take for the car to come to a full stop? Express your answer in terms of v0 and a0
Vf = 0
Vf = v0 - a0*t
0 = v0 - a0*t
a0*t = v0
t1 = v0/a0
B)
How much time does it take for the car to accelerate from the full stop to its original cruising speed? Express your answer in terms of v0 and a0.
at this point
U = 0
v0 = u + a0*t
v0 = 0 + a0*t
v0 = a0*t
t2 = v0/a0
C)
The train does not stop at the stoplight. How far behind the train is the car when the car reaches its original speed v0 again? Express the separation distance in terms of v0 and a0 . Your answer should be positive.
t1 = t2 = t
Distance covered by the train = v0 (2t) = 2v0t
and we know t = v0/a0
so distanced covered = 2v0 (v0/a0) = (2v0^2)/a0
now distance covered by car before coming to full stop
Vf2 = v0^2- 2a0s1
2a0s1 = v0^2
s1 = v0^2 / 2a0
After the full stop;
V0^2 = 2a0s2
s2 = v0^2/2a0
Snet = 2v0^2 /2a0 = v0^2/a0
Now the separation between train and car
= (2v0^2)/a0 - v0^2/a0
= v0^2/a0
Main Answer:
Assume that the temperature rises by 9.9 F
Initial Temperatures will be C1, F1
Final temperatures will be C2, F1 + 9.9
The relation between celsius and fahrenheit temperature is as follows:
C = 5/9(F - 32)
Increase in temperature in celsius will be
C2 - C1 = F2 - F1
C2 - C1 = 5/9 ( F1 +9.9 -32) - 5/9 ( F1 -32)
C2 - C1 = 5/9 ( F1 +9.9 -32 - F1 +32)
C2 - C1 = 5/9 (9.9)
C2 - C1 = 5.5C
Explanation:
What is temperature?
Temperature is defined as the degree of coldness or hotness of an object or a substance. Generally, it is measured in various temperature scales. They are celsius, fahrenheit, kelvin.
To know more about temperature, please visit:
brainly.com/question/25677592
#SPJ4
Answer:
(A). The electric field strength inside the solenoid at a point on the axis is zero.
(B). The electric field strength inside the solenoid at a point 1.50 cm from the axis is 
.
Explanation:
Given that,
Magnetic field = 2.0 T
Diameter = 5.0 cm
Rate of decreasing in magnetic field = 5.00 T/s
(A). We need to calculate the electric field strength inside the solenoid at a point on the axis
Using formula of electric field inside the solenoid
Electric field on the axis of the solenoid
Here, r = 0
The electric field strength inside the solenoid at a point on the axis is zero.
(B). We need to calculate the electric field strength inside the solenoid at a point 1.50 cm from the axis
Using formula of electric field inside the solenoid
Hence, (A). The electric field strength inside the solenoid at a point on the axis is zero.
(B). The electric field strength inside the solenoid at a point 1.50 cm from the axis is .
