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Andru [333]
3 years ago
6

Whenever an object is moving at a constant rate, the value(s) that equal zero is (are):

Physics
2 answers:
dolphi86 [110]3 years ago
5 0

Answer:

d) all of the above

Explanation:

the speed, velocity, and acceleration all changes to 0 due to no motion.

Xelga [282]3 years ago
3 0

Whenever an object is moving at a constant rate . . .

a).  its speed is that constant rate.

b).  Its <em>acceleration MAY BE zero</em>, if it's also moving in a straight line.

c).  Its velocity is that constant rate if it's moving in a straight line.  Otherwise, its velocity could have many different values, depending on the path it's following.  

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Please helppp
Y_Kistochka [10]

Answer:

F = 17.3 kN

Explanation:

The normal force must support the weight of the car plus provide for the needed centripetal acceleration.

F = m(g + v²/R ) = 1000(9.8 + 15²/30) = 17,300

6 0
3 years ago
The two particles are both moving to the right. Particle 1 catches up with particle 2 and collides with it. The particles stick
Irina18 [472]

Answer:

See bolded below.

Explanation:

Consider the " Before " and " After. " " Before, " this particle 1 was trying to catch up with this particle 2, and " after " particle one had collided with particle two. Take a look at the attachment below for a more detailed examination.

Here is how this will play out. Particle 1, with great velocity, will hit particle 2, which would mean that Particle 2 has less velocity than Particle 1. Now after the collision, energy is transferred to Particle 2, and while Particle 1 has now stopped in it's tracks, Particle 2 - with more energy than before - will continue as long as it has to before friction eventually brings it to a stop.

_______________________________________________________

From this we can conclude that Vf, from the picture below, must have less energy than V1, but more energy than V2 - and vice versa.

8 0
3 years ago
Two positive charges of 20 micro coulomb and 100 micro coulomb and the distance between them is 150cm.What will be the electrica
Roman55 [17]

Answer:

0.8 N

Explanation:

From coulomb's law,

Formula:

F = kqq'/r²........................ Equation 1

Where F = Force of repulsion, k = coulomb's constant, q = first positive charge, q' = second positive charge, r = distance between the charge.

Given: q = 20 μC = 20×10⁻⁶ C, q' = 100 μC = 100×10⁻⁶ C, r = 150 cm = 1.5 m.

Constant:  k = 9×10⁹ Nm²/C²

Substitute these values into equation 1

F = (20×10⁻⁶ )( 100×10⁻⁶)(9×10⁹)/1.5²

F = 1800×10⁻³/2.25

F = 1.8/2.25

F = 0.8 N

3 0
3 years ago
Which statement describes a characteristic of an experimental design that
Anarel [89]

Answer:

c

Explanation:

4 0
3 years ago
3) A 15.0kg cannonball is ascending after being launched. Neglect drag.
WINSTONCH [101]

Answer:

c

Explanation:

3 0
3 years ago
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