They undergo internal fertilization. They lose their tails as adults. They have wet, moist skin. They have long, strong legs. They begin life with gills.
Modern space suits augment the basic pressure garment with a complex system of equipment and environmental systems designed to keep the wearer comfortable, and to minimize the effort required to bend the limbs, resisting a soft pressure garment's natural tendency to stiffen against the vacuum. A self-contained oxygen supply and environmental control system is frequently employed to allow complete freedom of movement, independent of the spacecraft.
Three types of spacesuits exist for different purposes: IVA (intravehicular activity), EVA (extravehicular activity), and IEVA (intra/extravehicular activity). IVA suits are meant to be worn inside a pressurized spacecraft, and are therefore lighter and more comfortable. IEVA suits are meant for use inside and outside the spacecraft, such as the Gemini G4C suit. They include more protection from the harsh conditions of space, such as protection from micrometeorites and extreme temperature change. EVA suits, such as the EMU, are used outside spacecraft, for either planetary exploration or spacewalks. They must protect the wearer against all conditions of space, as well as provide mobility and functionality.
Here, you can derive that by numerical method, as follows:
F = m.a
m = F/a
So, here we can see when we decrease one, other increase by same effect; we can say they are "Indirectly Proportional" to each other!
Hope this helps!
Answer:
<em>The ball falls 0.3 m in the first 1/4 seconds, and it falls 0.92 m in the second 1/4 second</em>
Explanation:
<u>Horizontal Launch
</u>
When an object is thrown horizontally with a speed v from a height h, it describes a curved path ruled exclusively by gravity until it eventually hits the ground.
To calculate the vertical distance (y) traveled by the object in terms of the time (t) we use:
The fastball is thrown horizontally. The distance the ball falls in t=1/4 seconds = 0.25 seconds, is:
The distance the ball falls in t=1/2 seconds = 0.5 seconds is:
The distance it falls in the second 1/4 second is:
The ball falls 0.3 m in the first 1/4 seconds, and it falls 0.92 m in the second 1/4 second
Answer:
statement three and statement 2
Explanation
since they are weighted different, they will have more or less force (more mass=more force), also the heavier an object, the greater its acceleration while falling.
