Complete question:
while hunting in a cave a bat emits sounds wave of frequency 39 kilo hartz were moving towards a wall with a constant velocity of 8.32 meters per second take the speed of sound as 340 meters per second. calculate the frequency reflected off the wall to the bat?
Answer:
The frequency reflected by the stationary wall to the bat is 41 kHz
Explanation:
Given;
frequency emitted by the bat, = 39 kHz
velocity of the bat,
= 8.32 m/s
speed of sound in air, v = 340 m/s
The apparent frequency of sound striking the wall is calculated as;

The frequency reflected by the stationary wall to the bat is calculated as;


Answer:
The proton has much greater mass
Explanation:
- Protons and electrons are part of an atom
- Proton exists inside nucleus whereas electron keep moving around the nucleus
- Electrons have negative charge where as protons have positive charge .
Answer:
The only such elements are the Noble Gases (He, Ne, Ar, Kr, Xe, Rn)
(that is helium, neon, argon, krypton, xenon and radon)
Term: Monoatomic
Explanation:
Answer:
1 m/s
Explanation:
Impulse = Change in momentum
Force × Time = Mass(Final velocity) - Mass(Initial Velocity)
(1.0)(1.0) = (1.0)(Final Velocity) - (1.0)(0)
Final velocity = <u>1 m/s</u>