If you match the amount of static friction that can be generated when the object is at rest, it will not move because there is zero force the force has to be greater that the static friction in order to have it include motion. But if there was any more force will cause acceleration otherwise if it was lower force it will deceleration.
Answer:
The bird's speed immediately after swallowing is 6.17 m/s.
Explanation:
Given that,
Mass of the bird, m = 270 g = 0.27 kg
Initial speed of the bird, u = 5 m/s
Mass of the insect, m' = 11 g = 0.011 kg
Initial speed of the insect, u' = 35 m/s
We need to find the bird's speed immediately after swallowing. Let it is given by V. Using the conservation of momentum as :
So, the bird's speed immediately after swallowing is 6.17 m/s.
A) W=PE(1-cos0) ................