Find the height or length of these natural wonders in kilometers, meters, and centimeters.
1 answer:
A cave system with a mapped length of 369 miles:
594 km, 594,000 m, 59,400,000 cm
A waterfall that drops 1,180.8 ft :
0.35989 km, 359.89 m, 35,989 cm
A 20,250 ft tall mountain:
6.1738 km, 6,173.8 m , 617,380 cm
A canyon with a depth of 73,800 ft:
22.493 km, 22,493 m , 2,249,300 cm
Explanation:
Given:
The height or length of these natural wonders
To find:
The height or length of these natural wonders in kilometers, meters, and centimeters.
Solution:
(a) a cave system with a mapped length of 369 miles
Length of the cave system = 369 miles
(b) a waterfall that drops 1,180.8 ft
The height of the waterfall = 1,180.8 ft
(c) A 20,250 ft tall mountain.
The height of the mountain = 20.250 ft
(d) A canyon with a depth of 73,800 ft
The height of the canyon = 73,800 ft
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a) 779 kg m/s
The momentum of an object is given by:
p = mv
where
m is the mass of the object
v is its velocity
For the fullback before the collision,
m = 95 kg
v = 8.2 m/s
Therefore, his momentum was:
b) -779 kg m/s
After the collision, both the fullback and the tackle come to a stop: this means that their momentum after the collision is zero,
p' = 0
The initial momentum of the fullback was
p = 779 kg m/s
Therefore, his change in momentum is
where the negative sign indicates that the direction is opposite to the initial direction of motion.
c) -779 kg m/s
Here we can apply the law of conservation of momentum. In fact, the total momentum before and after the collision must be conserved. So we can write:
where
is the initial momentum of the fullback
is the initial momentum of the tackle
p' is the final combined momentum after the collision
We already know that
Therefore, we can find the tackle's original momentum:
where the negative sign indicates that the direction is opposite to the initial direction of motion of the fullback.
e) -6.1 m/s
To find the velocity of the tackle, we can use again the equation of the momentum:
p = mv
where here we have
is the original momentum of the tackle
m = 128 kg is his mass
Solving the equation for v, we find the tackle's original velocity:
So, he was moving at 6.1 m/s in the direction opposite to the fullback.