We can use Newton's second law to find out. This says F=ma, where m is the mass we seek:
So we see the mass is 3kg
Answer
given,
mass of the shell = 87 g = 0.087 Kg
speed of the muzzle = 853 m/s
mass of the helicopter = 4410 kg
A burst of 176 shell fired in 2.93 s
resulting average force = ?
momentum of the shell = m v
= 0.087 x 853
= 74.21 kgm/s
momentum of 176 shell is = 176 p
= 176 x 74.21
= 13060.96
momentum of helicopter = - 13060.96 kgm/s
amount of speed reduce a =
a=
a = 2.96 m/s²
velocity = \dfrac{2.96}{2.93}
v = 1.01 m/s
None of the above are the name of an air mass. This is probably a trick question.
Answer:
<h2>115 kg.m/s</h2>
Explanation:
The momentum of an object can be found by using the formula
momentum = mass × velocity
From the question we have
momentum = 23 × 5
We have the final answer as
<h3>115 kg.m/s</h3>
Hope this helps you
Since initial velocity is zero hence , u = 0
=> d = 1/2 * a * t2
on solving we get
d = 86.436 metres
Note ; Here Gravitational Acceleration is take as , g = 9.8 m/s2