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3 years ago

As pressure increased, temperature must ? For water to remain in a gaseous state.

Physics

1 answer:

Tasya [4]3 years ago

7 0

As pressure increases, temperature must increase for water to remain in a gaseous state.

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If the Sun were scaled down to the size of a grapefruit, about how far would you have to walk from our classroom to reach Alpha

Burka [1]

Answer:

2000 miles.

Explanation:

It's the Colorado scale model, in which sun is taken as the grapefruit and the distances are measured for different planets with respect to sun just for understanding.

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3 years ago

How many electrons are depicted in the electron dot diagram of an electrically neutral nitrogen atom? A. two B. six C. eight D.

goldenfox [79]

Answer is D - five.

Explanation;

- Electron dot diagrams show the valence electrons around the element by using dots.

- Valence electrons are the electrons which are in outermost shell of the atom.

-The atomic number of the N atom is 7.

Atomic number = number of protons = 7

If the atom is neutral,

number of protons = number of electrons.

Hence, N atom has 7 electrons.

- The electron configuration is 1s² 2s² 2p³.

Hence, N atom has 2 + 3 = 5 valence electrons. So, five electrons are represented in electron dot diagram of N.

4 0

3 years ago

Read 2 more answers

A rectangle has a length of (2.5 ± 0.2) m and a width of (1.5 ± 0.2) m. Calculate the area and the perimeter of the rectangle, a

eduard

You can just add the uncertainties

5 0

1 year ago

lanet R47A is a spherical planet where the gravitational acceleration on the surface is 3.45 m/s2. A satellite orbitsPlanet R47A

qaws [65]

$2.6×10^6\:\text{m}$

Explanation:

The acceleration due to gravity g is defined as

$g = G\dfrac{M}{R^2}$

and solving for R, we find that

$R = \sqrt{\dfrac{GM}{g}}\:\:\:\:\:\:\:(1)$

We need the mass M of the planet first and we can do that by noting that the centripetal acceleration $F_c$ experienced by the satellite is equal to the gravitational force $F_G$ or

$F_c = F_G \Rightarrow m\dfrac{v^2}{r} = G\dfrac{mM}{r^2}\:\:\:\:\:(2)$

The orbital velocity v is the velocity of the satellite around the planet defined as

$v = \dfrac{2\pi r}{T}$

where r is the radius of the satellite's orbit in meters and T is the period or the time it takes for the satellite to circle the planet in seconds. We can then rewrite Eqn(2) as

$\dfrac{4\pi^2 r}{T^2} = G\dfrac{M}{r^2}$