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Cerrena [4.2K]
3 years ago
5

Write a seminar on the constellations.

Physics
1 answer:
ivolga24 [154]3 years ago
8 0
You mean a essay. You gotta write that for yourself no one can’t fo it on Brainly for you
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Imagine that an electron in an excited state in a nitrogen molecule decays to its ground state, emitting a photon with a frequen
mash [69]
Since energy cannot be created nor destroyed, the change in energy of the electron must be equal to the energy of the emitted photon.

The energy of the emitted photon is given by:
E=hf
where
h is the Planck constant
f is the photon frequency
Substituting f=8.88 \cdot 10^{14}Hz, we find
E=hf=(6.6 \cdot 10^{-34} Js)(8.88 \cdot 10^{14} Hz)=5.86 \cdot 10^{-19} J

This is the energy given to the emitted photon; it means this is also equal to the energy lost by the electron in the transition, so the variation of energy of the electron will have a negative sign (because the electron is losing energy by decaying from an excited state, with higher energy, to the ground state, with lower energy)
\Delta E= -5.86 \cdot 10^{-19} J
6 0
3 years ago
Read 2 more answers
Electric Field of Ring of Charge A ring shaped charge has a radius of 0.250 meters and bears a total charge of +5.00 C What is t
Eduardwww [97]

Answer:

6.44 × 10^10 N/C

Explanation:

Electric field due to the ring on its axis is given by

E = K q r / (r^2 + x^2)^3/2

Where r be the radius of ring and x be the distance of point from the centre of ring and q be the charge on ring.

r = 0.25 m, x = 0.5 m, q = 5 C

K = 9 × 10^9 Nm^2/C^2

E = 9 × 10^9 × 5 × 0.25 / (0.0625 + 0.25)^3/2

E = 6.44 × 10^10 N/C

8 0
4 years ago
My Exams are coming.so, please tell me some ways to score good marks?​
Citrus2011 [14]

Instead of asking this question go and study

5 0
2 years ago
Read 2 more answers
Helpppppppp please !!!!
agasfer [191]

Answer:

second one is correct that is right

7 0
4 years ago
The graph in the accompanying figure (Figure 1) shows the magnitude of the force exerted by a given spring as a function of the
serious [3.7K]

The elastic potential energy stored in the stretched spring is 1 J.

<h3>What is Hooke's law?</h3>

Hooke's law states that; provided the elastic limit is not exceeded, the extension of the spring is directly proportional to the force on the spring.

Given that;

Force on the spring = 350 Newton

Distance stretched = 7 centimeters or 0.07 m

Hence;

F = ke

k = F/e = 350 Newton/0.07 m = 5000 N/m

Work done in stretching a spring = 1/2ke^2

= 0.5 × 5000 × (2 × 10^-2)^2 =1 J

Learn more about elastic potential energy: brainly.com/question/156316

4 0
2 years ago
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