How many Atoms are in 12 NaBr
1 answer:
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Given that solubility product of AgCl = 1.8 X 10^-10
Dissociation of AgCl can be represented as follows,
AgCl(s) ↔ Ag+(ag) + Cl-(aq)
Let, [Ag+] = [Cl-] = S
∴Ksp = [Ag+][Cl-] = S^2
∴ S = √Ksp = √(1.8 X 10^-10) = 1.34 x 10^-5 mol/dm3
Now, Molarity of solution =
∴ 1.34 x 10^-5 =
∴ Weight of AgCl present in solution = 1.92 X 10^-3 g
Thus, mass of AgCl that will dissolve in 1l water = 1.92 x 10^-3 g
Dissociation of AgCl can be represented as follows,
AgCl(s) ↔ Ag+(ag) + Cl-(aq)
Let, [Ag+] = [Cl-] = S
∴Ksp = [Ag+][Cl-] = S^2
∴ S = √Ksp = √(1.8 X 10^-10) = 1.34 x 10^-5 mol/dm3
Now, Molarity of solution =
∴ 1.34 x 10^-5 =
∴ Weight of AgCl present in solution = 1.92 X 10^-3 g
Thus, mass of AgCl that will dissolve in 1l water = 1.92 x 10^-3 g
<u>Answer:</u> The wavelength of the photon is 486.2 nm and it lies in the visible region
<u>Explanation:</u>
To calculate the wavelength of light, we use Rydberg's Equation:
Where,
= Wavelength of radiation
= Rydberg's Constant =
= Higher energy level = 4
= Lower energy level = 2
Putting the values in above equation, we get:
Converting this into nanometers, we use the conversion factor:
So,
As, the range of wavelength of visible light is 400 nm - 700 nm. So, the wavelength of the given photon lies in the visible region
Hence, the wavelength of the photon is 486.2 nm and it lies in the visible region