Answer:
5/4, 2, 9/4, 3, 3/1 (the last two are the same so it could go in either order)
Step-by-step explanation:
1 1/4, 2, 2 1/4, 3, 3
Step-by-step explanation:
Divide 140 by
to represent the amount of hours he worked.
To make dividing easier,
can also represent 2.8 as a decimal.

He has worked 50 hours after completing 140 rows of grapes.
To estimate, you should round some of the numbers to the closest number (rounding up or down). It will be more accurate the less you round. In this problem, we should round -5 1/4 to -5 since it is the closest. -5*-3/2 = 7.7. You will end up with -3/2x (-5 1/4) ≈ 7.5x
≈ means approximately equal.
Answer:
(a) E(X) = -2p² + 2p + 2; d²/dp² E(X) at p = 1/2 is less than 0
(b) 6p⁴ - 12p³ + 3p² + 3p + 3; d²/dp² E(X) at p = 1/2 is less than 0
Step-by-step explanation:
(a) when i = 2, the expected number of played games will be:
E(X) = 2[p² + (1-p)²] + 3[2p² (1-p) + 2p(1-p)²] = 2[p²+1-2p+p²] + 3[2p²-2p³+2p(1-2p+p²)] = 2[2p²-2p+1] + 3[2p² - 2p³+2p-4p²+2p³] = 4p²-4p+2-6p²+6p = -2p²+2p+2.
If p = 1/2, then:
d²/dp² E(X) = d/dp (-4p + 2) = -4 which is less than 0. Therefore, the E(X) is maximized.
(b) when i = 3;
E(X) = 3[p³ + (1-p)³] + 4[3p³(1-p) + 3p(1-p)³] + 5[6p³(1-p)² + 6p²(1-p)³]
Simplification and rearrangement lead to:
E(X) = 6p⁴-12p³+3p²+3p+3
if p = 1/2, then:
d²/dp² E(X) at p = 1/2 = d/dp (24p³-36p²+6p+3) = 72p²-72p+6 = 72(1/2)² - 72(1/2) +6 = 18 - 36 +8 = -10
Therefore, E(X) is maximized.
Answer:
14,300
Step-by-step explanation:
move the decimal 5 places to the right.
1.43 x 10^5= 14,300