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Law Incorporation [45]
3 years ago
10

A ball is equipped with a speedometer

Physics
1 answer:
Harman [31]3 years ago
3 0
The ball is launched with an upward speed of 50 m/s
2 seconds later it has 30m/s
At 5 seconds it stops
At 6 seconds it’s moving downwards with 10 m/s
At 7 seconds is moving with 20 m/s
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Which wave lies adjacent to the low frequency portion of the visible spectrum
fgiga [73]

Answer: b. infrared

Explanation:

The visible light with the smaller frequency is associated with the color red.

While the blue is the one with the larger frequency.

Now, as the name says, infrared waves are the ones with a frequency just below the one of the red visible light.

Where the frequency of the red light is something around (4.3*10^14 Hz)

and the frequency of the infrared waves is in the range between (10^12 Hz and 10^14 Hz)

Then the correct option is b, infrared.

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9. Compounds can form from two nonmetals by sharing their electrons in a
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3 years ago
The centrifugal force which tends to throw the electrons out it's orbit as stated with mass moving velocity in an orbit of radiu
sammy [17]

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An applied force of 20 N is used to accelerate an object to the right across a
vichka [17]

Answer:

F_{norm} = 100 N

F_{net}=10 N

\mu = 0.10

m = 10 kg

a=1.0 m/s^2

Explanation:

To determine the normal force, we just need to analyze the situation along the vertical direction.

The box along the vertical direction is in equilibrium, so the equation of the forces is

F_{norm} - F_{grav} = 0

which means that

F_{norm} = F_{grav} = 100 N

The net force can be determined by looking at the situation along the horizontal direction (since the net force in the vertical direction) is zero. Here we have:

- An applied force of 20 N forward, F_{app} = 20 N

- A frictional force of 10 N backward, F_{frict} = 10 N

So, the net force is

F_{net}=F_{app}-F_{frict}=20-10 = +10 N in the forward direction

The expression for the frictional force is

F_{frict} = \mu F_{norm}

where \mu is the coefficient of friction. Solving for \mu,

\mu = \frac{F_{frict}}{F_{norm}}=\frac{10}{100}=0.10

The force of gravity is given by

F_{grav}=mg

where m is the mass of the object and g=10 m/s^2. Solving for m, we find the mass of the object:

m=\frac{F_{grav}}{g}=\frac{100}{10}=10 kg

Finally, the acceleration can be found by using Newton's second law

F_{net} = ma

where a is the acceleration. Solving for a,

a=\frac{F_{net}}{m}=\frac{10}{10}=1.0 m/s^2

4 0
3 years ago
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