Answer:
0m/s²
Explanation:
A body with a constant speed always has a zero acceleration
Hence if Korey ran around the track at 10 meters per second and had a constant speed and did not change directions, then his acceleration will be 0m/s² not considering his initial speed
Answer:
2538.46N
Explanation:
Parameters given:
Initial speed, u = 0 m/s
Final velocity, v = 240 m/s
Time, t = 0.0052 s
Mass of club, m = 55g = 0.055 kg
First we find the acceleration:
a = (v - u)/t
a = (240 - 0)/0.0052
a = 46153.85 m/s²
Average force can then be found:
F = m*a
F = 0.055 * 46153.85
F = 2538.46 N
Answer:
a) μ = 0.602 and b) μ = 0.475
Explanation:
a) Let's use Newton's second law for this exercise. The reference system the x axis is parallel to the floor and the axis and perpendicular.
Y Axis
N-W = 0
N = W
X axis
F-fr = ma
The friction force equation is
fr = μN
At the point where the movement begins the acceleration is zero
Let's replace
F = μ (mg) = 0
F = μ mg
μ = F / mg
μ = 171/29 9.8
μ = 0.602
b) in this case we have the same formula, but the friction is kinetic
μ = F2 / mg
μ = 135/29 9.8
μ = 0.475