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3 years ago

12

Rosita went to the mall.She purchased a smoothie for $4,a scarf for $12,and a scrunchie for $8.Rosita plans to add 4+12+8 to det

ermine the total amount that she spent. Describe how Rosita can use the communicative property to more easily calculate the total

1 answer:

enyata [817]3 years ago

5 0

Answer:

4+12+8 = 24

Step-by-step explanation:

4+8=12 + 12 = 24 :)

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Simone saved $15.45 from allowance, had $7.37 in her piggy bank, and had $22.55 left from her birthday. How much money does Simo

zmey [24]

Simon has $45.37

Simone savings from allowance= $15.45

Amount Simone had in piggy bank = $7.37

Left over from birthday = $22.55

Total amount of money that Simone now has = $15.45 + $7.37 + $22.55

Total amount of money that Simone now has = $45.37

Simon has $45.37

Learn more here: brainly.com/question/20521181

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2 years ago

If f(x)=12x+2(x-1), find f(6)

zavuch27 [327]

Answer:

12x6+2(6-1)

72+2x5

72+10

82

82 is the answer.

Step-by-step explanation:

Just replace the X's in the problem with 6.

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3 years ago

The value of the investment is expected to grow by 3% per year.

disa [49]

3 times 24 is 48% therefore its D.

4 0

3 years ago

Read 2 more answers

Find a compact form for generating functions of the sequence 1, 8,27,... , k^3

pantera1 [17]

This sequence has generating function

$F(x)=\displaystyle\sum_{k\ge0}k^3x^k$

(if we include $k=0$ for a moment)

Recall that for $|x|$ , we have

$\displaystyle\frac1{1-x}=\sum_{k\ge0}x^k$

Take the derivative to get

$\displaystyle\frac1{(1-x)^2}=\sum_{k\ge0}kx^{k-1}=\frac1x\sum_{k\ge0}kx^k$

$\implies\dfrac x{(1-x)^2}=\displaystyle\sum_{k\ge0}kx^k$

Take the derivative again:

$\displaystyle\frac{(1-x)^2+2x(1-x)}{(1-x)^4}=\sum_{k\ge0}k^2x^{k-1}=\frac1x\sum_{k\ge0}k^2x^k$

$\implies\displaystyle\frac{x+x^2}{(1-x)^3}=\sum_{k\ge0}k^2x^k$

Take the derivative one more time:

$\displaystyle\frac{(1+2x)(1-x)^3+3(x+x^2)(1-x)^2}{(1-x)^6}=\sum_{k\ge0}k^3x^{k-1}=\frac1x\sum_{k\ge0}k^3x^k$

$\implies\displaystyle\frac{x+4x^3+x^3}{(1-x)^4}=\sum_{k\ge0}k^3x^k$

so we have

$\boxed{F(x)=\dfrac{x+4x^3+x^3}{(1-x)^4}}$

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3 years ago

Take away 8 from 5 times m

ch4aika [34]

Answer:

5m-8

Step-by-step explanation:

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3 years ago