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zimovet [89]
2 years ago
6

Can someone help me rq

Chemistry
2 answers:
Andru [333]2 years ago
5 0

Answer: there

Explanation:

kozerog [31]2 years ago
5 0
It’s 6,5,1,4,3,2 because the first guy said so
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Calculate the molarity of a NaOH solution that is prepared by diluting 100mL of 0.20M NaOH with 150mL of H2O.
lianna [129]

Molarity of solution = 0.08 M

<h3>Further explanation  </h3>

Molarity shows the number of moles of solute in every 1 liter of solution or mmol in each ml of solution  

\tt M=\dfrac{n}{V}  

Where  

M = Molarity  

n = number of moles of solute  

V = Volume of solution  

  • mol of NaOH

\tt mol=0.2~M\times 100~ml=20~mlmol=0.02~mol

  • molarity

Volume of solution = 100 ml + 150 ml = 250 ml

\tt M=\dfrac{0.02~mol}{0.250~L}=0.08

3 0
3 years ago
Why does chlorine displace bromine from potassium bromide solution
Nataliya [291]

Answer:

A more reactive halogen displaces a less reactive halogen from a solution of one of its salts.

Chlorine is more reactive than bromine, thus it displaces bromine.

4 0
3 years ago
The tendency of an object to resist change in its motion
spin [16.1K]
Inertia is the answer to this question
8 0
3 years ago
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Why is the speed of these particles deffirent in each state
monitta

Answer:

due to difference ic kinetic energy

Explanation:

3 0
3 years ago
How many moles are in 8.63 x 103 atoms of Li?
Ira Lisetskai [31]
<h3>Answer:</h3>

1.43 × 10⁻²⁰ mol Li

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>Explanation:</h3>

<u>Step 1: Define</u>

8.63 × 10³ atoms Li

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 8.63 \cdot 10^3 \ atoms \ Li(\frac{1 \ mol \ Li}{6.022 \cdot 10^{23} \ atoms \ Li})
  2. Multiply/Divide:                \displaystyle 1.43355 \cdot 10^{-20} \ moles \ Li

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

1.43355 × 10⁻²⁰ mol Li ≈ 1.43 × 10⁻²⁰ mol Li

4 0
3 years ago
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