Length=The distance between two points
Mass=The amount of matter contained in a body
Time=The interval or duration between two events
Temperature=The hotness and coldness of a body
The rate constant of a reaction : 8.3 x 10⁻⁴
<h3>Further explanation</h3>
Given
rate = 1 x 10⁻² (mol/L)/s, [A] is 2 M, [B] is 3 M, m = 2, and n = 1
Required
the rate constant
Solution
For aA + bB ⇒ C + D
Reaction rate can be formulated:
![\large{\boxed{\boxed{\bold{r~=~k.[A]^a[B]^b}}}](https://tex.z-dn.net/?f=%5Clarge%7B%5Cboxed%7B%5Cboxed%7B%5Cbold%7Br~%3D~k.%5BA%5D%5Ea%5BB%5D%5Eb%7D%7D%7D)
the rate constant : k =
![\tt k=\dfrac{rate}{[A]^m[B]^n}\\\\k=\dfrac{1.10^{-2}}{2^2\times 3^1}\\\\k=8.3\times 10^{-4}](https://tex.z-dn.net/?f=%5Ctt%20k%3D%5Cdfrac%7Brate%7D%7B%5BA%5D%5Em%5BB%5D%5En%7D%5C%5C%5C%5Ck%3D%5Cdfrac%7B1.10%5E%7B-2%7D%7D%7B2%5E2%5Ctimes%203%5E1%7D%5C%5C%5C%5Ck%3D8.3%5Ctimes%2010%5E%7B-4%7D)
Answer:
1.63 kilo Joules of energy will be produced when 14.8 g of silver nitrate react.
Explanation:

Mass of silver nitrate = 14.8 g
Moles of silver nitrate = 
According to reaction, when 1 mole of silver nitrate reacts with 1 mole of calcium it gives 18.7 kJ of heat.
Then amount of heat released when 0.08706 moles of silver nitrate reacts :

1.63 kilo Joules of energy will be produced when 14.8 g of silver nitrate react.
Answer:
See explanation
Explanation:
According to Hund's rule, electrons must occur singly first before pairing takes place.
If I want to fill six electrons into orbitals, the filling of electrons will be as follows;
1s2 2s2 2p2.
The first four electrons are filled into the 1s and 2s levels having only one orbital each. The fifth and sixth electrons are filled into 2p orbitals. The 2p level have three degenerate orbitals. The two electrons are singly filled into each of the degenerate orbitals in accordance to Hund's rule.