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3 years ago

At a high concentration do you have more or less particles per unit volume

Chemistry

1 answer:

Whitepunk [10]3 years ago

3 0

Answer:

More particles per unit volume

Explanation:

Concentration means the amount of solute in a solution. Now, the amount of solute also means the number of particles of solute present in a solution.

Hence, when we use the term "high concentration", we imply that the amount of solute present or the number of particles present in a solution is high.

Thus, at high concentration, there are more solute particles than solvent particles in a solution.

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How many grams of lead sulfide from when 10.0 g of lead are heated with 3.0 g of sulfur

zaharov [31]

The reaction forms 11.5 g PbS.

We have the masses of two reactants, so this is a limiting reactant problem.

We know that we will need a balanced equation with masses, moles, and molar masses of the compounds involved.

Step 1. Gather all the information in one place with molar masses above the formulas and everything else below them.

M_r: 207.2 32.06 239.28

Pb + S → PbS

Mass/g: 10.0 3.0

Step 2. Calculate the moles of each reactant

Moles of Pb = 10.0 g Pb × (1 mol Pb /207.2 g Pb) = 0.048 26 mol Pb

Moles of S = 30 g S × (1 mol S/32.06 g S) = 0.9357 mol S

Step 3. Identify the limiting reactant

Calculate the moles of PbS we can obtain from each reactant.

From Pb: Moles of PbS = 0.048 26 mol Pb × (1 mol PbS/1 mol Pb )

= 0.048 26 mol PbS

From S: Moles of S = 0.9357 mol S × (1 mol PbS/1 mol S) = 0.9357 mol PbS

Pb is the limiting reactant because it gives the smaller amount of PbS.

Step 4. Calculate the mass of PbS.

Mass = 0.048 26 mol PbS × (239.28 g PbS/1 mol PbS) = 11.5 g PbS

The reaction produces 11.5 g PbS.

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3 years ago

Do you think one type of engineer is more important that others? Defend your answer.

olchik [2.2K]

Answer:

Explanation:

All of the engineers today help us in many ways.

7 0

2 years ago

Read 2 more answers

Which of the following would most likely be caused by a tsunami?

Degger [83]

the answer Is A hope it helps

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3 years ago

Read 2 more answers

Each response gives a pair of solutions. which pair of solutions should conduct electrical current equally well? 1. 0.10 m nh3 a

Crazy boy [7]

Answer : The correct answer is option 2 : 0.10 M NaCl and 0.10 M NaClO₄

Explanation :

Solutions are classified into 3 categories.

1) Strong electrolytes : These are the solutions that dissociate completely forming ions . They are good conductors of electricity.

Example : All strong acids, bases and the salts made by strong acid/base are strong electrolytes .

2) Weak electrolytes : These substances do not dissociate completely thereby forming fewer ions. They are weak conductors of electricity.

3) Non electrolytes : These are the substances that do not dissociate at all. They do not form ions in aqueous medium. They are bad conductors of electricity.

Let us take a look at the given options and find out what type of solution do we have .

Option 1 : NH₃ is a weak electrolyte whereas NH₄Cl is a strong electrolyte bcause NH₄Cl is made by combination of NH₃ and HCl ( HCl is a strong acid)

Therefore NH₃ would carry electricity less efficiently than NH₄Cl.

Option 2 : Both NaCl and NaClO₄ are strong electrolytes. Therefore they will conduct electrical current equally well

Option 3 : NaNO₃ is a strong electrolyte but HNO₂ is a weak electrolyte. Therefore they will not carry the current equally

Therefore the correct option is option 2

3 0

4 years ago

Write the formulas for the analogous species of the elements of period 3; would you expect them to have the same hybridization a

ValentinkaMS [17]

Answer:

$AlH^-_4, SiH_4 \text{ and}\ PH^+_4$

Explanation:

The elements belonging to third period which corresponds to B,C and N are Al, Si and P. All these elements in the third period tries to combine with four of hydrogen atoms and form an analogous species.

The formulae of these species are given as $AlH^-_4, SiH_4 \text{ and}\ PH^+_4$

All these species have a central atom which has four electron domain and the geometry of the electron domain is tetrahedral. The hybridization which corresponds to the geometry of tetrahedral electron domain is $sp^3$ .

So $AlH^-_4, SiH_4 \text{ and}\ PH^+_4$ have the same hybridization at the central atom such as $BH^-_4, CH_4 \text{ and}\ NH^+_4$ .

4 0

3 years ago