What volume of 0.125 m kmno4 is required to yield 0.180 mol of potassium permanganate
1 answer:
Answer:
= 1.44 L
Explanation:
Molarity or concentration is given by the formula;
Molarity = moles/volume in L
Therefore;
Volume = moles/molarity
Number of moles = 0.180 moles
Molarity = 0.125 M
Thus;
Volume = 0.18 mol/ 0.125 M
= 1.44 L
<u>= 1.44 L</u>
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