Answer:
See below
Step-by-step explanation:
We first have to understand the parts of a y=mx+b equation
y=mx+b
m: Is the slope
b: Is the y-intercept
x: is the x part of (x,y)
y: is the y part of(x,y)
So...
if we use an example ordered pair like (1,3)
and a slope of 2
We can plug everything into y=mx+b to get
1=2*3+b which simplifies to b= -5
Now, you can use this concept to fill in the blanks below:
Use the two ordered pairs to find the slope, (m).
Then substitute the slope, and (one set of ordered pairs) into y=mx+b to solve for (b).
Answer:
A rectangular garden has dimensions of 19 feet by 16 feet. A gravel path of equal width is to be built around the garden. How wide can the path be if there is enough gravel for 246 square feet?
OA 5ft
OB. 3 ft
OC. 41
OD. 5.5 ft
(x+6)^(1/2)-5=x+1
(x+6)^(1/2)=x+6
((x+6)^(1/2))^2=(x+6)^2
x+6=x^2+12x+36
0=x^2+11x+30
(-11+(11^2-4(1)(30))^(1/2))/2
(-11+((1)^(1/2))/2
(-11+1)/2=-5
(-11-1)/2=-6
((-6)+6)^1/2-5=(-6)+1
(0^(1/2))-5=-5
-6 is non-extraneous
((-5)+6)^1/2-5=(-5)+1
(1^1/2)-5=-4
1-5=-4
-4=-4
-5 is non-extraneous
Answer:
x = 3 and x = -7
Step-by-step explanation:
The given quadratic equation is
. We need to find the solution of this equation.
If the equation is in the form of
, then its solutions are given by :
![x=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}](https://tex.z-dn.net/?f=x%3D%5Cdfrac%7B-b%5Cpm%20%5Csqrt%7Bb%5E2-4ac%7D%20%7D%7B2a%7D)
Here, a = 1, b = 4 and c = -21
Plugging all the values in the value of x, such that :
![x=\dfrac{-b+ \sqrt{b^2-4ac} }{2a},\dfrac{-b- \sqrt{b^2-4ac} }{2a}\\\\x=\dfrac{-4+ \sqrt{(4)^2-4\times 1\times (-21)} }{2(1)},\dfrac{-4- \sqrt{(4)^2-4\times 1\times (-21)} }{2(1)}\\\\x=3, -7](https://tex.z-dn.net/?f=x%3D%5Cdfrac%7B-b%2B%20%5Csqrt%7Bb%5E2-4ac%7D%20%7D%7B2a%7D%2C%5Cdfrac%7B-b-%20%5Csqrt%7Bb%5E2-4ac%7D%20%7D%7B2a%7D%5C%5C%5C%5Cx%3D%5Cdfrac%7B-4%2B%20%5Csqrt%7B%284%29%5E2-4%5Ctimes%201%5Ctimes%20%28-21%29%7D%20%7D%7B2%281%29%7D%2C%5Cdfrac%7B-4-%20%5Csqrt%7B%284%29%5E2-4%5Ctimes%201%5Ctimes%20%28-21%29%7D%20%7D%7B2%281%29%7D%5C%5C%5C%5Cx%3D3%2C%20-7)
So, the solutions of the quadratic equation are 3 and -7.