Answer:
To the nearest hundred dollars, the car will be worth $17,900 by 2005
Step-by-step explanation:
Firstly, we need to write the depreciation equation
We have this as:
V = I(1 - r)^t
V is the present value which is what we want to calculate
I is the initial value, the amount the cad was bought which is $22,000
r is the rate of change which is 5% = 5/100 = 0.05
t is the time difference which is 2005-2001 = 4
Substituting all these into the depreciation equation, we have it that
V = 22,000(1 -0.05)^4
V = $17,919.1375
To the nearest hundred dollars, that would be;
$17,900
Step-by-step explanation:
X(x+6) - 6(x+6)
X+6x-6x-36
X-36
Follow PEMDAS.
You would first do your distributive property which is, -5(z+2). You would multiply -5 to z and -5 to 2 which will give you -5z + -10.
so now you have 2z-5z+ -10= -8 - 2z. Now you must isolate the variable. So subtract -8 to -10 which will give you -18.
Now you have the equation 2z-5z-18=-2z
Now combine like terms. 2z-5z= -3z
Now you have the equation -3z-18=-2z
Now you must move the -3z to the other side of the equal sign by adding the opposite which is +3z to -2z which will give you +1z
Now you have -18= 1z
Now you divide. -18 divided by 1 is -18.
So your final answer will be -18=z
Answer:
10 tickets = 30$
20 = 60$
30 = 90$
40 = 120$
50 = 150$
