Answer:
a) 

b) From the central limit theorem we know that the distribution for the sample mean
is given by:
c)
Step-by-step explanation:
Let X the random variable the represent the scores for the test analyzed. We know that:

And we select a sample size of 64.
The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".
Part a
For this case the mean and standard error for the sample mean would be given by:


Part b
From the central limit theorem we know that the distribution for the sample mean
is given by:
Part c
For this case we want this probability:

And we can use the z score defined as:

And using this we got:
And using a calculator, excel or the normal standard table we have that:
Answer:
Step-by-step explanation:
16 x 28% = 4.48
16 x 72% = 11.52
16 x 172% = 27.52
16 x 128% = 20.48
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I dont know for the second one, sorry-
Answer:
4j + 2
Step-by-step explanation:
Distribute:
(2j * 2) + (1 * 2)
4j + 2
Answer:
6u+18
Step-by-step explanation:
6*u=6u and 6*3=18
Answer:
TUA=123
Step-by-step explanation:
so first we find <TUS in terms of x
so 180-11x-2
178-11x
so now we can use the sum of a triangle's angles which is always 180 to find the angles in triangle TUS
178-11x+5x+10+58=180
178-6x=112
take 178 from both sides
-6x=-66
x=11
so we can do 11x11+2=TUA
TUA=123