They are important because numerous serve as areas where water vapour can condense.
<h3>
</h3><h3>What is condensation?</h3>
The transformation of water vapour into liquid is known as condensation. The process is the opposite of evaporation, in which liquid water turns into a vapour. Either the air is chilled to its dew point or it gets too saturated with water vapour to retain any more water, causing condensation to occur.
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The moon's mass is only outnumbered by Earth's mass, which is 81 times greater. This indicates that while it moves in a circle, the circle is substantially smaller than usual. The core of the circle that the Earth revolves around is really inside the planet.
In space, there is gravity. It is gravity that makes the moon orbit. Everything in orbit, including the moon, is falling freely. That entails letting gravity operate as it pleases. Because you continually missing the object you are orbiting, an orbit is like a fall that never makes it to the earth; by the time you arrive at the spot where the object was, you have overshot, and it is now behind you.
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<span>A. No sound is heard
A*sin(wt)+(-A)*sin(wt)=0 - no sound
</span>
Answer:65 seconds
Explanation:just had the quiz
(a) The maximum height reached by the ball from the ground level is 75.87m
(b) The time taken for the ball to return to the elevator floor is 2.21 s
<u>The given parameters include:</u>
- constant velocity of the elevator, u₁ = 10 m/s
- initial velocity of the ball, u₂ = 20 m/s
- height of the boy above the elevator floor, h₁ = 2 m
- height of the elevator above the ground, h₂ = 28 m
To calculate:
(a) the maximum height of the projectile
total initial velocity of the projectile = 10 m/s + 20 m/s = 30 m/s (since the elevator is ascending at a constant speed)
at maximum height the final velocity of the projectile (ball), v = 0
Apply the following kinematic equation to determine the maximum height of the projectile.

The maximum height reached by the ball from the ground level (h) = height of the elevator from the ground level + height of he boy above the elevator + maximum height reached by elevator from the point of projection
h = h₁ + h₂ + h₃
h = 28 m + 2 m + 45.87 m
h = 75.87 m
(b) The time taken for the ball to return to the elevator floor
Final height of the ball above the elevator floor = 2 m + 45.87 m = 47.87 m
Apply the following kinematic equation to determine the time to return to the elevator floor.

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