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3 years ago

What runs all the way around the house but never moves?

2 answers:

8 0

The answer to the question is a fence, because it goes all the way around the house but once it is there it never moves :)

amm18123 years ago

6 0

<span>A fence runs all the way around the house but never moves.</span>

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Why do bones weaken as a person gets older

Sonbull [250]

Answer:

The bones aren't as strong as a younger person, because an older person, ages due to time and it also depend on what they do in their past.

Does this help? ^-^"

6 0

2 years ago

Find the magnitude of the average force ⟨Fx⟩⟨Fx⟩ in the x direction that the particle exerts on the right-hand wall of the conta

hodyreva [135]

Answer:

See explaination

Explanation:

Please kindly check attachment for the step by step solution of the given problem.

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3 years ago

Which line represents an object that is in motion where the acceleration is zero and the velocity is to the north?

Alex787 [66]

Answer:

what do the lines look like

3 0

2 years ago

Un prisma de cemento pesa 2500 N y ejerce una presión de 125 Pa, ¿cuál es el valor del área en la cual se apoya?

Eduardwww [97]

Answer:

Area = 20 m²

Explanation:

Given the following data;

Force = 2500 N

Pressure = 125 Pa

To find the area on which it rest;

Mathematically, pressure is given by the formula;

$Pressure = \frac {Force}{area}$

Making area the subject of formula, we have;

$Area = \frac {Force}{pressure}$

Substituting into the formula, we have;

$Area = \frac {2500}{125}$

Area = 20 m²

3 0

3 years ago

Wagon wheel. While working on your latest novel about settlers crossing the Great Plains in a wagon train, you get into an argum

OverLord2011 [107]

Answer:

I = 16.7kgm²

Explanation:

Since, Torque is given by,

\tau = F*r = I*\alpha

here, I = Moment of inertia = ??

\alpha = angular acceleration of wheel = a/r

F = tangential tension acting on the wheel = T

a = acceleration of bag of sand = 2.95 m/s^2

r = radius of wheel = d/2 = 120/2 = 60 cm = 0.60 m

from force balance on sand bag,

mg - T = m*a

T = m*(g-a)

m = mass of sand bag = 20 kg

So, I = T*r/\alpha = m*(g-a)*r/(a/r)

Using known values:

I = 20*(9.81 - 2.95)*0.60/(2.95/0.60) = 16.74

I = 16.7 kgm² = Moment of inertia of wheel experimentally

also, Moment of inertia of wheel theoretically(I') = M*r²

given, M = mass of wheel = 70 kg

I' = 70*0.60²= 25.2 kgm² = Moment of inertia of wheel theoretically

7 0

3 years ago