In an Internal Combustion Engine, the fuel is singed in the chamber or vessel. Example: Diesel or Petrol motor utilized as a part of Cars.
The internal engine has its vitality touched off in the barrel, as 99.9% of motors today. In an External Combustion Engine, the inner working fuel is not consumed. Here the liquid is being warmed from an outer source. The fuel is warmed and extended through the interior instrument of the motor bringing about work. Eg. Steam Turbine, Steam motor Trains. An outer burning case is a steam motor where the warming procedure is done in a kettle outside the motor.
Answer:
Therefore,
The magnitude of the force per unit length that one wire exerts on the other is

Explanation:
Given:
Two long, parallel wires separated by a distance,
d = 3.50 cm = 0.035 meter
Currents,

To Find:
Magnitude of the force per unit length that one wire exerts on the other,

Solution:
Magnitude of the force per unit length on each of @ parallel wires seperated by the distance d and carrying currents I₁ and I₂ is given by,

where,

Substituting the values we get


Therefore,
The magnitude of the force per unit length that one wire exerts on the other is

Answer:
it will be curved as in deceleration
Explanation:
Given data
ball throws upwards at an angle 60°
Horizontal component (Vh) = 12.5 m/s,
Vertical component (Vv) = 21.7 m/s ,
The magnitude of throw/resultant velocity (V) = ?
The resultant velocity /the velocity with which ball is throws is determined by the following equation
V = √[(Vh)² + (Vv)²]
= √[(12.5)² + (21.7)²]
= 25.04 m/s
<em> The resultant velocity or the velocity with which the ball is thrown is 25 m/s</em>
Answer:C
Explanation:
Partially submerged block along with vessel is accelerated upwards .
Initially the block weight is supported by buoyant force such that it is in equilibrium.
when the system start accelerating upwards then the effective gravity will be
g+a where a is the acceleration of the system.
so only net gravity is increased so block will not ascend or descend.
Mathematically


where
density of liquid
V=volume of object inside the water