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1 year ago

The end that points southward is called

Physics

1 answer:

Zepler [3.9K]1 year ago

7 0

Answer:

Explanation: The end of the magnet that points towards the south is called the north-seeking end or the south pole of the magnet.

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Nobel gases share which characteristics?

Leto [7]

Full outer shell of electrons, they are colorless and odorless ,their melting and boiling points are close together which gives them very narrow liquid range

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2 years ago

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Calculate the magnitude of the electric field 2.00 m from a point charge of 5.00 mC (such as found on the terminal of a Van de G

MakcuM [25]

Answer:

The magnitude of the electric field is 1.124 X 10⁷ N/C

Explanation:

Magnitude of electric field is given as;

$E = \frac{kq}{r^2} , N/C$

where;

E is the magnitude of the electric field, N/C

q is the point charge, C

k is coulomb's constant, Nm²/C²

r is the distance of the point charge, m

Given;

q = 5mC = 5×10⁻³ C

r = 2m

k = 8.99 × 10⁹ Nm²/C²

Substitute these values and solve for magnitude of electric field E

$E = \frac{kq}{r^2} = \frac{(8.99 X10^9)(5X10^{-3})}{2^2} = 1.124 X10^7 N/C$

Therefore, the magnitude of the electric field is 1.124 X 10⁷ N/C

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2 years ago

A typical human contains 5.00 l of blood, and it takes 1.00 min for all of it to pass through the heart when the person is resti

Mrrafil [7]

<span>(a) 0.0676 l (b) 67.6 cc So we've been told that 5.00 L of blood flows through the heart every minute and that the heart beats 74.0 times per minute. So that means that for every beat of the heart, 5.00 L / 74.0 = 0.067567568 L of blood flows through the heart. Rounding to 3 significant figures gives 0.0676 l. Converting from liters to cubic centimeters simply require a multiplication by 1000, so we have 67.6 cc of blood pumped per beat.</span>

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2 years ago

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Suppose we could shrink the Earth without changing its mass. At what fraction of its current radius would the free-fall accelera

spin [16.1K]

Answer:

$R' = \frac{1}{\sqrt{3}}R$

Explanation:

The acceleration due to gravity on the surface of the Earth is given by:

$g=\frac{GM}{R^2}$

where

G is the gravitational constant

M is the mass of the Earth

R is the radius of the Earth

Here we want to find the new Earth radius R' for which the gravitational acceleration at the surface, g', would be 3 times the current value of g:

$g' = 3g$

So we would have

$\frac{GM}{R'^2}=3(\frac{GM}{R^2})$

Solving the equation for R', we find

$R'^2 = \frac{1}{3}R^2\\R' = \frac{1}{\sqrt{3}}R$

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2 years ago

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A 70.-kilogram cyclist develops 210 watts of

Temka [501]

The Definition of Potence is given by:

$P=Fv$

Entering the unknowns:

$P=Fv \\ 210=7F \\ F= \frac{210}{7} \\ \boxed {F=30N}$

Number 2

If you notice any mistake in my english, please let me know, because i am not native.

8 0

3 years ago