I think it’s KE I could be wrong tho
Answer:
30 seconds
Explanation:
The formula for calculating acceleration is
( final velocity - inital velocity) ÷ time
If we enter the values, it would be (250 - 100) ÷ t = 5m/s^2
Now we need to know 't'
So we rearrange the equation to make t the subject.
(250-100) ÷ 5 = 30s
Answer:
a) v = 5.88 m/s
b) v = 11.76 m/s
c) s = 1.764 m
d) s = 7.056 m
Explanation:
Given,
The initial velocity of the steel ball, u = o
The acceleration due to gravity, g = 9.8 m/s²
The equations of motion to find the final velocity for a body under free fall with an initial velocity, u = 0 is
v = u + at m/s
v = at m/s
a) At time t = 0.6 s
v = 9.8 x 0.6
= 5.88 m/s
The velocity of the ball 0.6 seconds after its release is, v = 5.88 m/s
b) At t = 1.2 s
v = 9.8 x 1.2
= 11.76 m/s
The velocity of the ball 1.2 seconds after its release is, v = 11.76 m/s
The distance traveled by the free falling body is given by the formula
s = ut + 1/2 at² m
s = 1/2 at² ∵ u = 0
c) At, t = 0.6 s
s = 1/2 x 9.8 x 0.6²
= 1.764 m
The distance ball fall in the first 0.6 seconds of its flight is, s = 1.764 m
d) At, t = 1.2 s
s = 1/2 x 9.8 x 1.2²
= 7.056 m
The distance ball fall in the first 1.2 seconds of its flight is, s = 7.056 m
To find average speed, we can use the formula:
speed(m/s) = total distance (m) / time (s)
total distance = 4km + 3km = 7km = 7000m
time = 1.5 hours = 5400s
speed = 7000/5400 = 1.30m/s
To find average velocity, we can use the same formula, but replacing total distance with total displacement.
total displacement = 5km = 5000m (if we use the distance to Sheila's house and the distance from her house to the supermarket as the vector arrows for vector addition, we get 5km, as stated in the question)
velocity = 5000/5400 = 0.926m/s
Because this is a velocity, we need the direction. To find this we can use the formula:
tan (theta) = opposite / adjacent
tan (theta) = 3000/4000
sin(tan (theta))^-1 = sin (3000/4000)^-1
theta = 48.6° East of North or 41.4° North of East
So the average velocity is 0.926m/s [48.6° East of North/ 41.4° North of East]
Answer:
the order of arrival is from highest to lowest
star other side of Andromeda> star near side of andromeda> other side of milky way > center of the milky way> nevulosa orion> Pluto> Sum
Explanation:
The light that comes from stars and galaxies travels in a vacuum so its speed is constant and with a value of c = 3 108 m / s, so time will be directly proportional to the distance to the object
x = c t
the order of arrival is from highest to lowest
star other side of Andromeda> star near side of andromeda> other side of milky way > center of the milky way> nevulosa orion> Pluto> Sum
