Question

The electric potential inside a parallel-plate capacitor __________.

Answer 1

Answer:

$\Delta V=\frac{Q d}{A \epsilon_0}$

Explanation:

for the calculation of the electric potential inside a parallel plate capacitor you can use the formula for the electric field inside the capacitor.

$\Delta V=V(d)-V(0)=\int_0^dEdx$

where d is the distance between plates and E is the electric field, which is given by:

$E=\frac{\sigma}{\epsilon_0}$

By replacing you obtain:

$\Delta V=E\int_0^ddx=Ed=\frac{\sigma d}{\epsilon_0}=\frac{Qd}{A\epsilon_0}$

where Q is the charge stored by the capacitor and A is the area of the plates.

hence, the answer is Qd/Ae0