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astraxan [27]
2 years ago
14

PLEASE HELP ME!!!!!!!!

Physics
1 answer:
Valentin [98]2 years ago
4 0

i m soryyyyyyyyyyyyyy....

...

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The Hubble telescope’s orbit is 5.6 × 105 meters above Earth’s surface. The telescope has a mass of 1.1 × 104 kilograms. Earth e
djverab [1.8K]
The gravitational field is the Force divided by the mass

Call g the gravitational fiel, F the force exerted by the earth and m the mass of the telescope.

g = F / m


g=9.1x10^4 N / 1.1 x 10^4 kg = 8.27 N/kg

Note that the unit N/kg is equivalent to m/s^2

 
8 0
3 years ago
driving down the highway , you find yourself behind a heavily loaded tomato truck. you follow close behind the truck keeping the
prohojiy [21]

Answer:

The tomato won't hit the car

Explanation:

According to the statement, the car moves at constant speed behind the truck fully loaded with tomatoes, and in the same direction. When a tomato falls from the top of the truck, it should not hit the car as the tomato falls due to the force of gravity, while horizontally has the same speed and in the same direction as the truck.  So we assume that the tomato will fall to the road without touching the car.

Have a nice day!

4 0
3 years ago
What is the magnitude and direction (right or left) of the
Sunny_sXe [5.5K]

Answer: 12 N to the right

Explanation:

If we calculate the net force acting on the box, we will have:

<u>In y-component:</u>

Fy_{net}=F_{n}+F_{g} (1)

Where F_{n}=12 N is the Normal force, directed upwards and F_{g}=-12 N is the weight of the box (gravity force), directed downwards.

Fy_{net}=12 N-12 N (2)

Fy_{net}=0 N (3) Hence the net force in the vertical component is zero

<u>In x-component:</u>

Fx_{net}=F_{left}+F_{right} (4)

Where F_{left}=-3 N and F_{right}= 15 N

Fx_{net}=-3 N + 15 N (5)

Fx_{net}=12 N (6) This is the net force in the horizontal component

Therefore, the total net force acting on the box is 12 N directed to the right

5 0
3 years ago
greater than: The electric potential energy of a proton at point A is _____ the electric potential energy of an proton at point
mestny [16]

Answer:

[similar to]

Explanation:

it is the missing word

3 0
3 years ago
B) A satellite with mass m orbits the Earth at a radius r. A second satellite also with mass m orbits the
Snezhnost [94]

Answer:

So, given the eqn Fg=G(m1+m2/r^2) where G is the gravitational constant, m is the mass of the satellite and m2 is the mass of the earth and r is the distance from earth to the satellite, the force of earths gravity should be quartered.

Cause (2r)^2 gets turned into (4r^2) where 4r^2 is compared to r^2

Explanation:

6 0
3 years ago
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