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Naya [18.7K]
2 years ago
5

Write the products for the following neutralization reactions

Physics
1 answer:
madam [21]2 years ago
5 0

Answer:

answer 3

Explanation:

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A camera with a 50.0-mm focal length lens is being used to photograph a person standing 3.00 m away. (a) How far from the lens m
kirill [66]

a) 50.8 mm

b) The whole image (1:1)

c) It seems reasonable

Explanation:

a)

To project the image on the film, the distance of the film from the lens must be equal to the distance of the image from the lens. This can be found by using the lens equation:

\frac{1}{f}=\frac{1}{p}+\frac{1}{q}

where

f is the focal length of the lens

p is the distance of the object from the lens

q is the distance of the image from the lens

In this problem:

f = 50.0 mm = 0.050 m is the focal length (positive for a convex lens)

p = 3.00 m is the distance of the person from the lens

Therefore, we can find q:

\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{0.050}-\frac{1}{3.00}=19.667m^{-1}\\q=\frac{1}{19.667}=0.051 m=50.8 mm

b)

Here we need to find the height of the image first.

This can be done by using the magnification equation:

\frac{y'}{y}=-\frac{q}{p}

where:

y' is the height of the image

y = 1.75 m is the height of the real person

q = 50.8 mm = 0.0508 m is the distance of the image from the lens

p = 3.00 m is the distance of the person from the lens

Solving for y', we find:

y'=-\frac{qy}{p}=-\frac{(0.0508)(1.75)}{3.00}=-0.0296 m=-29.6mm

(the negative sign means the image is inverted)

Therefore, the size of the image (29.6 mm) is smaller than the size of the film (36.0 mm), so the whole image can fit into the film.

c)

This seems reasonable: in fact, with a 50.0 mm focal length, if we try to take the picture of a person at a distance of 3.00 m, we are able to capture the whole image of the person in the photo.

3 0
3 years ago
Which of these is NOT an effect of humor?
IgorLugansk [536]
Feelings of jealousy and envy
7 0
3 years ago
A simple compass can be made by placing a small bar magnet on a cork floating in water.
tankabanditka [31]

Answer:

yes

Explanation:

4 0
3 years ago
How is the path of the water particles near the water's surface different from the path near the ocean floor
swat32

Answer: Cold Ocean Currents: It is the layer of the ocean water which moves due to the stress of blowing the wind and this motion is thus called as Ekman Transport. Deep Water Currents: They constitute about 90% of the ocean water. They move around the ocean basin due to variations in the density and gravity.

7 0
2 years ago
Which figure represents the electric field lines of two positive point charges?
Naddik [55]

Electric field lines of positive charges are always radially outwards

So here all field lines must have tendency to move out radially as well as two field lines never intersects with each other

So here field lines also do not intersects with each other

So overall the figure C is perfectly representing the field lines of two positive charges as these lines are not intersecting and also originating from two positive charges.

So answer must be

<u><em>FIGURE C</em></u>

7 0
3 years ago
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