Given :
A mover slides a refrigerator weighing 650 N at a constant velocity across the floor a distance of 8.1 m. 
The force of friction between the refrigerator and the floor is 230 N.
To Find :
How much work has been performed by the mover on the refrigerator.
Solution :
Since, refrigerator is moving with constant velocity.
So, force applied by the mover is also 230 N ( equal to force of friction ).
Now, work done in order to move the refrigerator is :

Hence, this is the required solution.
 
        
             
        
        
        
Mechanical digestion is chewing, and chemical digestion is the saliva in your mouth breaking down food.
        
                    
             
        
        
        
V = IR
I = V/R
I = 12/6
I = 2 amps
        
                    
             
        
        
        
Yes it does.
On the periodic table, tin is #50 and Mercury is # 80. 
        
             
        
        
        
Heat = change in internal energy + Work done The internal energy of a system = heat added and mechanical work done by the system, i.e. U = Q + W rearranging the formula above, will give us: Q = deltaU + W 
Q = U - W = 604 kJ - 43.0 kJ = 561,000 J would be the answer.