As the spring returns to it's equilibrium position, it performs
1/2 (4975 N/m) (0.097 m)² ≈ 23 J
while the gravitational force (opposing the block's upward motion) performs
-(0.244 kg) g<em> </em>(0.097 m) ≈ -2.3 J
of work on the block. By the work energy theorem, the total work done on the block is equal to the change in its kinetic energy:
23 J - 2.3 J = 1/2 (0.244 kg) v² - 0
where v is the speed of the block at the moment it returns to the equilibrium position. Solve for v :
v² = (23 J - 2.3 J) / (1/2 (0.244 kg))
v = √((23 J - 2.3 J) / (1/2 (0.244 kg)))
v ≈ 44 m/s
After leaving the spring, block is in free fall, and at its maximum height h it has zero vertical velocity.
0² - (44 m/s)² = 2 (-g) h
Solve for h :
h = (44 m/s)² / (2g)
h ≈ 2.3 m
The colours we see are the wavelengths that are reflected or transmitted. For example, a red shirt looks red because the dye molecules in the fabric have absorbed the wavelengths of light from the violet/blue end of the spectrum.
Answer:
Option C. 16.6 m/s
Explanation:
To round this 16.558 m/s to 3sf, we need to count the number beginning from 1. When we get to the 3rd number( ie 5), we'll examine the fourth number(i.e 5)to see if it less than five or greater. If it less than five, then we'll discard it. But if it five or greater, we'll approximate it and add it to the 3rd number.
So.
16.558 m/s = 16.6m/s to 3sf
Answer:
11.625 Ohm
Explanation:
Let V be the Voltage charge of the loop, as this is constant we know that before the resistor addition the current I is:
V/R1 = 1.9 or V = 1.9R1
After the resistor addition to series R = R1 + 3.1
I = V/R = V/(R1 + 3.1) = 1.5
We can substitute V = 1.9R1
1.9R1 = 1.5R1 + 1.5*3.1
0.4R1 = 4.65
R1 = 4.65/0.4 = 11.625 Ohm
Answer: 4 ohms
Explanation:
For parallel connection we use this formula
R=equivalent resistance
R1=24 ohms
R2=8 ohms
R3=12 ohms
1/R=1/R1 + 1/R2 + 1/R3
1/R=1/24 + 1/8 + 1/12
1/R=(1x1+3x1+2x1) ➗ 24
Cross multiplying we get
24x1=(1x1+3x1+2x1) x R
24=(1+3+2) x R
24=6xR
Divide both sides by 6
24 ➗ 6=6xR ➗ 6
4=R
R=4 ohms
