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Fittoniya [83]
2 years ago
7

Which type of reaction does this chemical equation represent? 2Na + MgCl2 - 2NaCl + Mg

Physics
2 answers:
Kipish [7]2 years ago
8 0

The answer is in fact c

Airida [17]2 years ago
5 0

Answer: Single replacement

Explanation: A P E X

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Difference between on pitch and frequency​
shepuryov [24]

Answer:

 A high pitch sound corresponds to a high frequency sound wave and a low pitch sound corresponds to a low frequency sound wave. I hope I got it correct !!

8 0
3 years ago
Please answer the one you know!
tresset_1 [31]
#8 positive kinetic energy
3 0
2 years ago
A vector has an x-component
9966 [12]

Explanation:

The magnitude of a vector v can be found using Pythagorean's theorem.

||v|| = √(vₓ² + vᵧ²)

||v|| = √((-309)² + (187)²)

||v|| ≈ 361

You can find the angle of a vector using trigonometry.

tan θ = vᵧ / vₓ

tan θ = 187 / -309

θ ≈ 149° or θ ≈ 329°

vₓ is negative and vᵧ is positive, so θ must be in the second quadrant.  Therefore, θ ≈ 149°.

4 0
3 years ago
In a Hall-effect experiment, a current of 3A sent lengthwise through a conductor of 1 cm wide, 4 cm long,
Marina CMI [18]

Answer:drift velocity is 1.7*10^-4m/s and number of charge is 2.7*10^-24

Explanation:

4 0
3 years ago
A car is strapped to a rocket (combined mass = 661 kg), and its kinetic energy is 66,120 J.
aliina [53]

Answer:

9.43 m/s

Explanation:

First of all, we calculate the final kinetic energy of the car.

According to the work-energy theorem, the work done on the car is equal to its change in kinetic energy:

W=K_f - K_i

where

W = -36.733 J is the work done on the car (negative because the car is slowing down, so the work is done in the direction opposite to the motion of the car)

K_f is the final kinetic energy

K_i = 66,120 J is the initial kinetic energy

Solving,

K_f = K_i + W = 66,120 + (-36,733)=29,387 J

Now we can find the final speed of the car by using the formula for kinetic energy

K_f = \frac{1}{2}mv^2

where

m = 661 kg is the mass of the car

v is its final speed

Solving for v, we find

v=\sqrt{\frac{2K_f}{m}}=\sqrt{\frac{2(29,387)}{661}}=9.43 m/s

3 0
3 years ago
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