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Triss [41]
3 years ago
8

Pam, with a mass of 40.4 kilograms, straps on a rocket pack while wearing her roller blades. The rocket supplies a constant forc

e for 26.7 meters, and Pam acquires a speed of 26.0 meters per second. a. What is Pam's final kinetic energy
Physics
1 answer:
barxatty [35]3 years ago
4 0

Answer:

13.66 kJ

Explanation:

Given that

Mass of Pam, m = 40.4 kg

Distance moved by the force, d = 26.7 m

Speed attained by Pam, v = 26 m/s

The kinetic energy is given by the formula, K.E = 1/2 mv², where

K.E = the needed kinetic energy

m = mass of the object(Pam)

v = velocity of the object(Pam)

Applying the formula, we have

K.E = 1/2 * 40.4 * 26²

K.E = 20.2 * 676

K.E = 13655.2 J

The Kinetic Energy is 13.66 kJ

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One horse is pulling a 755 kg sled straight ahead applying a force of 1988 N. If the acceleration of the sled is 1.36 m/s2, what
Inessa [10]

Answer:

The coefficient of kinetic friction is 0.13

Explanation:

Newton's second law states that the acceleration of an object is proportional to the net force on it, the factor of proportionality is the mass. So, we can express that law mathematically as:

\sum\overrightarrow{F}=m\overrightarrow{a} (1)

With F the net force, m the mass and a the acceleration of the object. In our case we're interested on what's happening to the sled, then we have to analyze the forces on it, those forces are the weight and the normal force on the vertical direction and the pulling force and frictional force in the horizontal direction. So, because (1) is a vector equation we can express that in their vertical (y) and horizontal (x) components:

F_y=ma_y (2)

F_x=ma_x (3)

On y we have that the acceleration is zero because the sled is not moving upward or downward, remember that the net force on y is the weight (W) pointing downward and the normal force pointing upward:

F_y=W+n=0

Following the convention that positive is upward and negative downward, W=mg=(755)(-9.81):

F_y=(755)(-9.81)+n=0

n=7406.55 N (4)

Now on the x direction we have the sum of the forces is the pulling force (T) and friction force (f)

F_x=F+f=ma_x

Choosing the direction where the horse is pulling F=1988N and the acceleration should be positive too, then:

1988+f=m(1.36)

f=(755)(1.36)-1988=-961.2 N

The negative sign means it's in the opposite direction the horse is pulling

The frictional force is related with the coefficient of kinetic friction in the next way:

|f|=\mu_k n

with μk the coefficient of kinetic friction, and n the normal force that we already found on (4), so we simply solve the last equation for μk:

\mu_k=\frac{|f|}{n}=\frac{961.2}{7406.55}=0.13

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grandymaker [24]
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How did scientists discover the Earth had a liquid outer core and solid inner core?
viktelen [127]
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4 years ago
Which of the following provides evidence that geologic activity occurred in the past on Earth's Moon?
Bingel [31]

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Explanation:

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The surface features of moon such as Mares, Craters, mountains, Rays and rills are the proof of some geological activity on the Moon. Mares are the dark patches on the moon's surface formed of solidified lava. Due to negligible atmosphere on the moon, the meteors strike its surface and cause craters to form. Thus, the correct answer is d.

6 0
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A force of 880 newtons stretches a spring 4 meters. A mass of 55 kilograms is attached to the end of the spring and is initially
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Answer:

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