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const2013 [10]
3 years ago
10

PLEASE HElP ASAP!!!!!!

Chemistry
1 answer:
stepan [7]3 years ago
7 0

Answer:

1 hour

Explanation:

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It took 55 days for a radioactivity of 1.75 x 1012 Bq to remain 0.135 Ci. What is the half-life of this radioactivity?
Mnenie [13.5K]

From the calculations, the half life of the material is 6.5 days.

<h3>What is radioactivity?</h3>

The term radioactivity has to do with the spontaneous disintegration of a specie.

Uisng the formula;

N=Noe^-kt

N= amount at time t = 0.135 Ci or 4.995 ×10^9 Bq

No = amount initially present =  1.75 x 10^12 Bq

k = rate constant = ?

t = time taken = 55 days

Hence;

4.995 ×10^9  = 1.75 x 10^12e^-55k

4.995 ×10^9/1.75 x 10^12 = e^-55k

2.85 * 10^-3 = e^-55k

ln2.85 * 10^-3 = -55k

k = ln2.85 * 10^-3/-55

k = 0.1066 day-1

Half life = 0.693/ 0.1066 day-1

= 6.5 days

Learn more about radioactivity:brainly.com/question/1770619

#SPJ1

4 0
2 years ago
What is it called when scientists write out a compound such as two hydrogen and one oxygen? PLEASE HELP
schepotkina [342]
A compound is when two or more elements are joined together. The compound that is created with two hydrogens and one oxygen is h2o or water.
7 0
3 years ago
When substances combine to form mixtures they keep their properties.<br> O<br> True<br> O<br> False
Gnesinka [82]

Answer:

True

Explanation:

8 0
3 years ago
Read 2 more answers
X-x/4-1/3=2+x/4 please answer me ​
Karo-lina-s [1.5K]

Answer:

x= 14/3 = 4.667

Explanation:

X - X/4 - 1/3 = 2 + X/4

7 0
3 years ago
g Ammonium nitrate was the oxidizing agent used that damaged the New York World Trade Center in 1993 and the Federal Building in
Cloud [144]

Answer:  51.3\times 10^3 kJ

Explanation:

The thermochemical equation for decomposition of ammonium nitrate is:

NH_4NO_3(s)\rightarrow N_2O(g)+2H_2O(g)   \Delta H=-82.1kJ

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass= 50.0 kg =50.0\times 10^3g   (1kg=1000g)

\text{Number of moles of ammonium nitrate}=\frac{50.0\times 10^3g}{80g/mol}=0.625\times 10^3moles

According to stoichiometry:

1 mole of NH_4NO_3 gives = 82.1 kJ of heat

Thus 0.625\times 10^3moles of NH_4NO_3 give =\frac{82.1}{1}\times 0.625\times 10^3=51.3\times 10^3  kJ of heat

Thus 51.3\times 10^3 kJ of heat is evolved from the decomposition of 50.0 kg of ammonium nitrate.

7 0
3 years ago
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