The molarity of the solution of H₃PO₄ needed to neutralize the KOH solution is 0.35 M
<h3>Balanced equation </h3>
H₃PO₄ + 3KOH —> K₃PO₄ + 3H₂O
From the balanced equation above,
- The mole ratio of the acid, H₃PO₄ (nA) = 1
- The mole ratio of the base, KOH (nB) = 3
<h3>How to determine the molarity of H₃PO₄ </h3>
- Volume of acid, H₃PO₄ (Va) = 10.2 mL
- Molarity of base, Ca(OH)₂ (Mb) = 0.2 M
- Volume of base, Ca(OH)₂ (Vb) = 53.5 mL
- Molarity of acid, H₃PO₄ (Ma) =?
MaVa / MbVb = nA / nB
(Ma × 10.2) / (0.2 × 53.5) = 1 / 3
(Ma × 10.2) / 10.7 = 1 / 3
Cross multiply
Ma × 10.2 × 3 = 10.7
Ma × 30.6 = 10.7
Divide both side by 30.6
Ma = 10.7 / 30.6
Ma = 0.35 M
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A regular pentagon may be divided into 5 congruent triangles.
If the side of the pentagon is 6 feet, each base of the triangles will be 6 feet.
If the distance from the center to a vertex is 6 feet, all the sides of the triangles will 6 feet.
So there are 5 congruent, equilateral triangles each with side equal to 6 feet.
The area one of those triangles is calculateb by:
base * height / 2
height ^2 = (side length) ^2 - (side length /2)^2 = 6^2 - 3^2 = 36 - 9 = 27
=> height = √(27) ≈ 5.2 feet
And, using area = base * height / 2 ,
area of a triangle = 6 feet * 5.2 feet / 2 = 15.6 feet^2
And the area of the entire pentagon equals 5 triangles ≈ 5 * 15.6 feet^2 = 78 feet^2
Answer: 78 feet^2
Answer : The moles of given compound is, 0.064 mole
Explanation : Given,
Mass of given compound = 40 g
Atomic mass of X = 50 amu
Atomic mass of Y = 45 amu
Atomic mass of Z = 10 amu
First we have to calculate the molar mass of given compound.
The given compound formula is, 
Molar mass of = (5 × Atomic mass of X) + (7 × Atomic mass of Y) + (6 × Atomic mass of Z)
Molar mass of = (5 × 50) + (7 × 45) + (6 × 10) = 625 g/mol
Now we have to calculate the moles of given compound.
Thus, the moles of given compound is, 0.064 mole
