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Irina18 [472]
3 years ago
6

An 80-kg astronaut becomes separated from his spaceship. He is 15.0 m away from it and at rest relative to it. In an effort to g

et back, he throws a 500 gram object with a speed of 8.0 m/s in a direction away from the ship. How long does it take him to get back to the ship?
Physics
1 answer:
Allushta [10]3 years ago
3 0

Answer: 300 s

Explanation:

The momentum p is given by the following equation:

p=m.V

Where m is the mass of the object  and V is the velocity.

In addition, according to the conservation of linear momentum, we have:

p_{1}=p_{2} (1)

Where:

p_{1}=0 is the initial momentum of the astronaut, which is initially at rest

p_{2}=m_{object}V_{object}+m_{astronaut}V_{astronaut} is the final momentum, being m_{object}=500g=0.5 kg, V_{object}=8 m/s and  m_{astronaut}=80 kg

Then (1) is rewritten as:

0=m_{object}V_{object}+m_{astronaut}V_{astronaut} (2)

Finding te velocity of the astronaut V_{astronaut}:

V_{astronaut}=-\frac{m_{object}V_{object}}{m_{astronaut}} (3)

V_{astronaut}=-\frac{(0.5 kg)(8 m/s)}{80 kg} (4)

V_{astronaut}=-0.05 m/s (5) The negative sign of the velocity indicates it is directed towards the spaceship, however its speed (the magnitude of the velocity vector) is positive 0.05 m/s

On the other hand we have the following:

V_{astronaut}=\frac{d}{t} (6)

Where d=15 m the distance between the astronaut and the spacheship and t the time. So, we have to find t:

t=\frac{d}{V_{astronaut}} (7)

t=\frac{15 m}{0.05 m/s}

Finally:

t=300 s

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Answer:

The maximum voltage is 41.92 V.

Explanation:

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f=\dfrac{1}{2\pi\sqrt{0.380\times1.20\times10^{-8}}}

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A projectile is launched
Flauer [41]

The vertical component of the velocity after the given time is -9.8 m/s while the horizontal component of the velocity is 16 m/s.

The given parameters;

  • initial horizontal velocity, vₓ = 16 m/s
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  • time interval 1 seconds

The components of the velocity can be horizontal or vertical velocity.

The vertical component of the velocity is affected by acceleration due to gravity while the horizontal component of the velocity is not affected by gravity.

The vertical component of the velocity is calculated as;

v_y = v_0_y -gt\\\\v_y = 0 - (1\times 9.8)\\\\v_y = -9.8 \ m/s

The horizontal component of the velocity is constant since it is not affected by gravity.

The horizontal component of the velocity = 16 m/s

Thus, the vertical component of the velocity after the given time is -9.8 m/s while the horizontal component of the velocity is 16 m/s.

Learn more here:brainly.com/question/20349275

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