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Svet_ta [14]
2 years ago
15

An rv is traveling 60 km/h along a highway at night. a boy sitting near the driver of the rv turns a flashlight on and shines it

at another boy at the back end of the rv. what is the speed of the light relative to the boys? m/s what is the speed of light relative to a stationary observer on the side of the road? m/s
Physics
1 answer:
nika2105 [10]2 years ago
3 0

Speed of light relative to the boys = 300,000,000 m/s

Speed of light relative to a stationary observer on the side of the road =

<h3>300,000,000 m/s</h3><h3>What is special theory of relativity?</h3>
  • The theory of special relativity explains how speed affects space, time, and mass.
  • Small amounts of mass (m) can be interchangeable with large amounts of energy (E), as defined by the classic equation E = mc2, according to the theory, which offers a means for the speed of light to define the link between energy and matter.

<h3>What are the special relativity's guiding principles?</h3>
  • The laws of physics should be independent of the uniform motion of an inertial frame of reference, and the speed of light should be constant in any such frame, according to two fundamental tenets that constitute the basis of the special theory of relativity.

To learn more about special relativity visit:

brainly.com/question/12497537

#SPJ4

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Anna [14]

Answer:

1.4s

Explanation:

Given parameters:

Mass of ball  = 2kg

Force  = 8N

Time  = 0.35s

Unknown:

Change in velocity  = ?

Solution:

To solve this problem, we use the expression obtained from Newton's second law of motion which is shown below:

      Ft  = m(v  - u)

 So;

         Ft  = m Δv

F is the force

t is the time

m is the mass

Δv is the change in velocity

             8 x 0.35  = 2 x Δv

                  Δv  = 1.4s

6 0
2 years ago
What is the velocity of a proton that has been accelerated by a potential difference of 15 kV? (i)\:\:\:\:\:9.5\:\times\:10^5\:m
andre [41]

Answer:

Velocity of a proton, v=1.7\times 10^6\ m/s    

Explanation:

It is given that,

Potential difference, V=15\ kV=15\times 10^3\ V

Let v is the velocity of a proton that has been accelerated by a potential difference of 15 kV.

Using the conservation of energy as :

\dfrac{1}{2}mv^2=qV

q is the charge of proton

m is the mass of proton

v=\sqrt{\dfrac{2qV}{m}}

v=\sqrt{\dfrac{2\times 1.6\times 10^{-19}\ C\times 15\times 10^3\ V}{1.67\times 10^{-27}\ kg}

v=1695361.75\ m/s

v=1.69\times 10^6\ m/s

or

v=1.7\times 10^6\ m/s

So, the velocity of a proton is 1.7\times 10^6\ m/s. Hence, this is the required solution.

8 0
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Tresset [83]

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Explanation:

In the case when approx 50% only of the solar energy would be directed towards earth and it would be penetrates directly to the surface so the rest or remaining of the radiation would be either absorbed or refected by the atmosphere

So as per the given situation the above represent the answer

hence, the same is to be considered and relevant

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Two boys wearing roller skates are standing on a smooth surface with the palms of their hands touching and their arms bent, as s
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