In an experiment if doubling the manipulated variable results in doubling of the responding variable the relationship between th
1 answer:
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Answer:
6.3 m/s
Explanation:
m = mass of the block = 1.10 kg
k = spring constant of the spring
x = stretch in the spring = 0.2 m
t = time taken by block to come to zero speed first time = 0.100 s
T = Time period of oscillation
Time period of oscillation is given as
T = 2t
T = 2 (0.1)
T = 0.2 s
Time period is also given as
k = 1084.6 N/m
v = maximum speed of the block
using conservation of energy
Maximum kinetic energy = Maximum spring potential energy
(0.5) m v² = (0.5) k x²
m v² = k x²
(1.10) v² = (1084.6) (0.2)²
v = 6.3 m/s
Answer:
D) Vertically.
Explanation:
A free body diagram is used to represent all the forces acting in a body. forces like, the force of gravity as a result of the gravitational interaction between the object and the Earth (W), the frictional force opposite to the movement of the object (), the normal force due to the plane and the object (N) and the force applied to start the movement in a particular direction (F).
As is show in the free body diagram of the system, W, which is the weight of the body as a consequence of the gravitational force, is at an angle below the inclined plane. that angle between the plane and the x axis is the same that the one of the inclined plane with respect to the horizontal, Since its sides are perpendicular.
Notice how W goes always in the direction to the center of mass of Earth in a vertical path (For comparison see figure (a) and (b)).
Answer:
Coil 2 have 235 loops
Explanation:
Given
The number of loops in coil 1 is n ₁= 159
The emf induced in coil 1 is ε ₁ = 2.78 V
The emf induced in coil 2 is ε ₂ = 4.11 V
Let
n ₂ is the number of loops in coil 2.
Given, the emf in a single loop in two coils are same. That is,
ϕ ₁/n ₁= ϕ ₂ n ₂⟹ 2.78/159 = 4.11/ n ₂
n₂=
n₂=235
Therefore, the coil 2 has n ₂= 235 loops.