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raketka [301]
3 years ago
14

In an experiment if doubling the manipulated variable results in doubling of the responding variable the relationship between th

e variable is a(n)?
Physics
1 answer:
vodomira [7]3 years ago
6 0
In an experiment if doubling the manipulated variable results in doubling of the responding variable the relationship between the variable is a direct. Having a direct relationship means that the<span> relationship between two numbers or other variables where an increase or decrease in one variable causes the same change to the other variable.</span>
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Plants cause weathering, too. a seed that falls into a crack in a rock may grow there. growing roots may push on and enlarge the
Helga [31]

The process which involves plants to cause weathering to a seed that falls into a crack in a rock therefore, breaking apart the rock is called Mechanical weathering.

<h3>Mechanical weathering</h3>

This is defined as the set of weathering processes that break apart rocks into particles (sediment) through physical processes. The most common form of mechanical weathering is the freeze-thaw cycle. Water seeps into holes and cracks in rocks then the water freezes and expands, therefore making the holes larger eventually making the rock split apart.

Read more on Mechanical weathering:

brainly.com/question/857495

3 0
2 years ago
Pre-laboratory Assignment: Experiment 20 Reflection and Refraction of Light 1. When light is incident on a reflective surface, w
shusha [124]

Answer:

1) ngle of incidence and reflection are equal,  light carries does not change

2) the angle of this line with respect to the surface is 90º

3) protractor

4)    n₂  sin θ₂ = n_1 sin θ₁,  light ray must have a greater angle than the incident ray ,

Explanation:

1) When light falls on a reflective surface, the angle of incidence and reflection are equal and as it travels in the same medium, the speed that the light carries does not change

2) The normal is a line perpendicular to the point of incidence of light, so the angle of this line with respect to the surface is 90º

3) Angles are measured with a protractor

4) When light passes from one medium to another, the speed of the ray changes due to the difference in the refractive index in each medium, due to this change in speed the transmitted light ray must have a greater angle than the incident ray , since the speed increases as the density of the medium decreases

           \frac{sin \theta _2}{ sin \theta_1} = \frac{v_2}{v_1}

          \frac{c}{v_2} \  sin \theta_2 = \frac{c}{v_1}  \ sin \theta_1

          n₂  sin θ₂ = n_1 sin θ₁

6 0
3 years ago
A camera lens focuses on an
natka813 [3]
0.556cm height of image
5 0
2 years ago
A ball is thrown with an initial velocity of 20 m/s at an angle of 60° above the horizontal. If we can neglect air resistance, (
Neporo4naja [7]

Answer:

10 m/s

1.87914 s

18.7914 m

Explanation:

v = Initial velocity = 20 m/s

\theta = Angle = 60°

Horizontal component is given by

v_x=20cos60\\\Rightarrow v_x=10\ m/s

The horizontal component is 10 m/s

y direction final displacement is zero

s=vsin \theta t+\frac{1}{2}at^2\\\Rightarrow 0=20sin60+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{2\times 20sin 60}{9.81}}\\\Rightarrow t=1.87914\ s

The time the ball is in the air is 1.87914 s

Range is given is by

R=vcos\theta t\\\Rightarrow R=10\times 1.87914\\\Rightarrow R=18.7914\ m

The range is 18.7914 m

6 0
3 years ago
Captain Jack Sparrow has been marooned on an island in the Atlantic by his crew, and decides to builda raft to escape. The wind
Marianna [84]

Answer:

    d₃ = 37,729 km,     θ=  5.1º North of West

Explanation:

This is a velocity addition problem, the easiest way to solve it is to decompose the velocities in a Cartesian system, the x-axis coincides with the West-East direction and the y-axis with the South-North direction

* first displacement is

           d₁ₓ = 11 km

* second offset is

          cos 6 = d₂ₓ / d₂

          sin 6 = d_{2y} / d₂

          d₂ₓ = d₂ cos 6

          d_{2y} = d₂ sin 6

          d₂ₓ = 6 cos 6 = 5.967 km

          d_{2y} = 6 sin 6 = 0.6272 km

* third displacement is unknown

* fourth and last displacement

          cos (-11) = d₄ₓ / d₄

          sin (-11) = d_{4y} / d₄

          d₄ₓ = d₄ cos (-11)

          d_{4y} = d₄ sin (-11)

          d₄ₓ = 21 cos (-11) = 20.61 km

          d_{4y} = 21 sin (-11) = -4.007 km

They tell us that at the end of the tour you are back on the island, so the displacement must be zero

X axis

           x = d₁ₓ + d₂ₓ + d₃ₓ + d₄ₓ

           0 = 11 +5.967 + d₃ₓ + 20.61

           d₃ₓ = -11 - 5.967 - 20.61

           d₃ₓ = -37.577 km

Y axis  

          y = d_{1y} + d_{2y} + d_{3y} + d_{4y}

          0 = 0 + 0.6272 + d_{3y} -4.007

          d_{3y} = 4.007 - 0.6272

          d_{3y} = 3.3798 km

This distance can be given in the form of module and angle

Let's use the Pythagorean theorem for the module

           d₃ = \sqrt{d_{3x}^2 + d_{3y}^2}

           d₃ = \sqrt{37.577^2 + 3.3798^2}

           d₃ = 37,729 km

Let's use trigonometry for the angle

            tan θ = d_{3y} / d₃ₓ

            θ = tan⁻¹ \frac{d_{3y}}{d_{3x}}

            θ = tan-1 (-3.3798 / 37.577)

            θ = 5.1º

Since the y coordinate is positive and the x coordinate is negative, this angle is in the second quadrant, so the direction given in the form of cardinal coordinates is

            θ=  5.1º North of West

3 0
3 years ago
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