The final speed of the orange is 7.35 m/s
Explanation:
The motion of the orange is a free fall motion, since there is only the force of gravity acting on it. Therefore, it is a uniformly accelerated motion with constant acceleration towards the ground. So we can use the following suvat equation:
where
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time elapsed
For the orange in this problem, we have
u = 0 (it is dropped from rest)
is the acceleration
Substituting t = 0.75 s, we find the final velocity (and speed) of the orange:
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Answer:
Vector K = 8 m
Explanation:
The given figure shows a right angle triangle JKL. It is given that :
vector L = 10 m
vector J = 6 m
We have to find vector k. We can find it by using Pythagoras theorem. According to this theorem, the sum of squares of perpendicular and the base is equal to the square of the longest side.
K = 8 m
Hence, the magnitude of vector K is 8 m.