Refer to the above attachment
A 1.5 kg orange falls from a tree and hits the ground in 0.75s. What is the speed of the orange just before it hits the ground?
1 answer:
The final speed of the orange is 7.35 m/s
Explanation:
The motion of the orange is a free fall motion, since there is only the force of gravity acting on it. Therefore, it is a uniformly accelerated motion with constant acceleration towards the ground. So we can use the following suvat equation:
where
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time elapsed
For the orange in this problem, we have
u = 0 (it is dropped from rest)
is the acceleration
Substituting t = 0.75 s, we find the final velocity (and speed) of the orange:
Learn more about free fall:
#LearnwithBrainly
You might be interested in
Answer:
The option (b) is correct.
Explanation:
The expression for the power in terms of work done is as follows;
Here, W is the work done, t is the time taken and P is the power.
According to the given problem, six identical resistors are connected in series with a battery. The number of joules per second supplied by the battery is then determined.
The expression for the equivalent resistance in the series combination is as follows;
R_{eq}=R_{1}+R_{2}......+R_{6}
Put R_{1},R_{2}......,R_{6}=R.
R_{eq}=R+R+R+R+R+R
R_{eq}=6R
It is given in the problem that a seventh resistor is added (in series).
R_{eq}=R_{1}+R_{2}......+R_{7}
Put R_{1},R_{2}......,R_{7}=R.
R_{eq}=R+R+R+R+R+R+R
R_{eq}=7R
The expression for the power in terms of voltage and resistance is as follows;
Here, R is the resistance.
From the above expression, it can be concluded that the power, the number of joules per second supplied by the battery is inversely proportional to the resistance. The equivalent resistance increases if the seventh resistance is connected with a battery.
If a seventh resistor is added (in series) the number of joules per second supplied by the battery decreases.
Therefore, the option (b) is correct.