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Westkost [7]
3 years ago
5

Name any ten trainings that provide the opportunity of foreign employment​

Chemistry
1 answer:
Alisiya [41]3 years ago
4 0

Answer:

• Abogado

• Administrador o conservacionista de campo

• Agrícola o agrónomo

• Apiculturísta

• Arquitecto

• Arquitecto ambiental

• Asistente de investigación

• Astrónomo

• Bioquímico

• Científico animal

• Científico avícola

• Científico de suelo

• Consejero vocacional

• Contador

• Criador animal

• Economista

• Entomólogo

• Epidemiólogo

• Farmacólogo

• Físico

• Fitogenetista

• Forestal

• Genetista

• Geoquímico

• Geofísico

• Horticultor

• Ingeniero

• Matemático (incluyendo estadístico)

• Meteorólogo

• Nutriólogo

• Profesor

• Químico

• Silviculturiasta (incluyendo forestalista)

• Terapeuta recreativo

• Topógrafo

• Trabajador social

• Urbanista (incluyendo geógrafo)

• Zoologísta

• Técnico científico de cualquiera de las siguientes disciplinas: ciencias agrícolas, astronomía, biología, química, ingeniería, silvicultura, geología, geofísica, meteorología o física

Explanation:

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Initial volume: mL

Final volume: mL

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All cells must have energy to function. Most of the energy used by the cells in your body is produced by cellular respiration. I
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Leopard seals are animals adapted to survive in the freezing conditions of Antarctica. Individual leopard seals vary in their di
andreev551 [17]

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B. Thicker layer of blubber

Explanation:

For the leopard seals to survives this harsh environment, it must have a thicker layer of blubber

Blubber is a thick layer of fat. It is called the adipose tissues and found in most marine organisms.

  • This layer helps in insulating the body against heat loss.
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6 0
3 years ago
Calculate the boiling point of a solution of 500.0 g of ethylene glycol (c2h6o2) dissolved in 500.0 g of water. kf = 1.86°c/m a
Bingel [31]

Answer:The boiling point of the solution is 108° C.

Explanation:

Boiling point of pure water=T=100^oC

Boiling point of water after addition of 500 g of ethylene glycol=T_f

Mass of water = 500g = 0.5 kg (1000 g = 1 kg)

\Delta T_f=K_b\times \frac{\text{Mass of ethlyene glycol}}{\text{Molar mass of ethylene glycol}}

\Delta T_f=0.512^oC/m\times \frac{500 g}{62.07 g/mol\times 0.5 kg}

\Delta T_f=8.24 ^oC

\Delta T_f=T_f-T

8.24^oC=T_f-100^oC

T_f=108.24^oC

The boiling point of the solution is 108° C.

7 0
3 years ago
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