Find the circumference.<br> Use 3.14 for pi<br> r = 4 cm<br> C = [?] cm<br> C=pi d

Joshua started cycling at 5:15 pm By 8:09 pm, he has covered a distance of 7250 mWhat was Joshua's average speed during that tim

vivado [14]

The average speed of Joshua during that time is 2500 m/h.

Explanation:

It is given that Joshua started cycling at 5:15 pm. By 8:09 pm he has covered a distance of 7250 m.

The total time taken by Joshua from 5:15 pm to 8:09 pm is

$2 { h } 54 \text { min }=2 \mathrm{h}+\frac{54}{60} {h}$

Dividing we get,

$2 { h } 54 \text { min }=2 \mathrm{h}+0.9 {h}$

Adding, we have,

$2 { h } 54 \text { min }=2.9 {h}$

Thus, the total time taken by Joshua is $2.9 {h}$

To determine the average speed we use the formula,

$speed=\frac{distance}{time}$

where $distance=7250$ and $time=2.9$

Hence, substituting the values we have,

$speed=\frac{7250}{2.9}$

Dividing, we get,

$speed=2500$

Thus, the average speed of Joshua during that time is 2500 m/h.

5 0

3 years ago

Eric has 5 CDs that he is going to give away. He lets his best friend choose 3 of the 5 CDs. How many different groups of 3 CDs

Snowcat [4.5K]

Given a group of n object. We want to make a selection of k objects out of the n object. This can be done in

C(n, k) many ways, where $C(n, k)= \frac{n!}{k!(n-k)!}$ ,

where k!=1*2*3*...(k-1)*k

Thus, we can do the selection of 3 cd's out of 5, in C(5,3) many ways,

where

$C(5, 3)= \frac{5!}{3!2!}= \frac{5*4*3*2*1}{3*2*1*2*1}= \frac{5*4}{2}=10$

Answer: 10

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=494%20divided%20by%2019%2C594" id="TexFormula1" title="494 divided by 19,594" alt="494 divided

Vaselesa [24]

0.02521179 jdjdjdduhdbdjdhdhj

3 0

2 years ago

Tammy bought 20 pounds of flour for $11.<br> How many pounds of flour did she get per dollar?

frozen [14]

Answer:

1.82 pounds per dollar

Step-by-step explanation:

20/11= 1.82

6 0

3 years ago

Read 2 more answers

Mateo teaches a continuing education class at the library on tuesday nights. he estimates that 75% of his students are satisfied

vredina [299]

The computed value must closely match the real value for a model to be considered valid. If the percentage of pleased or very satisfied students remains close to 75% after Mateo surveys additional students, Mateo's model is still viable. The model is faulty if the opposite is true.

<h3>How will mateo know whether his model is valid or not?</h3>

In general, a valid model is one whose estimated value is close to the real value. This kind of model is considered to be accurate. It must be somewhat near to the real value if it doesn't resemble the real value.

If the findings of the survey are sufficiently similar to one another, then the model may be considered valid.

P1 equals 75%, which is the real assessment of the number of happy pupils

P2 is 70 percent; this represents the second assessment of happy pupils

In conclusion, The estimated value of a model has to be somewhat close to the real value for the model to be considered valid. If the number of students who are either pleased or extremely satisfied remains close to 75 percent following Mateo's survey of more students, then Mateo's model is likely accurate. In any other scenario, the model cannot be trusted.

Find the circumference. Use 3.14 for pi r = 4 cm C = [?] cm C=pi d