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Hitman42 [59]
2 years ago
5

Question 16 of 25

Physics
1 answer:
slava [35]2 years ago
5 0
The answer is B because trust me
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Ice floats on water but iron nail sinks in it why give reason?<br>​
levacccp [35]

Explanation:

If you like my answer than please mark me brainliest thanks

4 0
3 years ago
The wheels of an automobile are locked as it slides to a stop from an initial speed of 30.0 m/s. If the coefficient of kinetic f
Amiraneli [1.4K]

Answer:

  x = 76.5 m

Explanation:

Let's use Newton's second law at the point of contact between the wheel and the floor.

     fr = m a

     fr = miy N

     N-W = 0

     N = W

     μ mg = m a

     a = miu g

    a = 0.600 9.8

    a = 5.88 m / s²

Having the acceleration we can use the kinematic relationships to find the distance

     v_{f}² = v₀² + 2 a x

    v_{f} = 0

    x = -v₀² / 2 a

Acceleration opposes the movement by which negative

   x = - 30²/2 (-5.88)

   x = 76.5 m

8 0
3 years ago
At locations A and B, the electric potential has the values VA = 1.83 V and VB = 5.17 V, respectively. A proton released from re
densk [106]

Answer:

a. It starts at point B.

vp = 2.53*10⁴ m/s

a. it starts at point A.

ve= 1.08*10⁶ m/s

Explanation:

a)  As the proton is a positive charge, when released from rest, it will be accelerated due to the potential difference, from the higher potential to the lower one, so it is at the point B when released.

Once released, as the total energy must be conserved, the increase in kinetic energy must be equal (in magnitude) to the change in the electric potential energy, as follows:

ΔK + ΔUe = 0 ⇒ ΔK = -ΔUe =- (e*ΔV)

⇒ -( e* (VA-VB) ) = \frac{1}{2}*mp*v^{2}

where e= elementary charge= 1.6*10⁻¹⁹ C,  VA = 1.83 V, VB= 5.17V, and mp= mass of proton = 1.67*10⁻²⁷ kg.

Replacing by these values, and solving for v, we have:

v = \sqrt{\frac{2*1.6e-19C*3.34 V}{1.67e-27kg} } = 2.53e4 m/s

⇒ vp = 2.53*10⁴ m/s

b) If, instead of a proton, the charge realeased from rest, had been an electron, a few things would change:

First, as the electrons carry negative charges, they move from the lower potentials to the higher ones, which means that it would have started at point A.

Second, as its charge is (-e) the change in electric potential energy had been negative also:

ΔUe = -e*ΔV = -e* (VB-VA)

In order to find the speed of the electron when it is just passing point B, we can apply the conservation of energy principle as for the proton, as follows:

-( (-e)* (VB-VA) ) = \frac{1}{2}*me*v^{2}

where e= elementary charge= 1.6*10⁻¹⁹ C,  VA = 1.83 V, VB= 5.17V, and me= mass of electron = 9.1*10⁻³¹ kg.

Replacing by these values, and solving for v, we have:

v = \sqrt{\frac{2*1.6e-19C*3.34 V}{9.1e-31kg} } = 1.08e6 m/s

⇒ ve = 1.08*10⁶ m/s

4 0
3 years ago
7. Which of the following is NOT always true about a synthesis reaction!
Rainbow [258]

Answer:

C

Explanation:

the formula is a + b = ab

5 0
3 years ago
Which describes an image that a concave mirror can make? Which describes an image that a concave mirror can make?
Shkiper50 [21]

Answer:

the image can be rather real or virtual

3 0
2 years ago
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