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Hitman42 [59]
2 years ago
5

Question 16 of 25

Physics
1 answer:
slava [35]2 years ago
5 0
The answer is B because trust me
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Solid barium sulfate is placed into a beaker to form a saturated solution of barium sulfate. the solution has a barium concentra
borishaifa [10]
Ksp = [Ba⁺²][SO₄⁻²]

[Ba⁺²] = [SO₄⁻²] for barium sulfate
Thus,
Ksp = (1 x 10⁻⁵)²
Ksp = 1 x 10⁻¹⁰
5 0
2 years ago
Read 2 more answers
When approaching an intersection, bridge, or railroad crossing, you should never drive (pass on the left half of the roadway whe
e-lub [12.9K]
You should not go into the left side of the roadway when within 100 feet of the crossing. Moreover, you should also turn on your turn signal when within 100 of a turn. These precautions prevent accidents as it makes clear to other drivers what your intentions are and drivers making turns are not endangered. 
8 0
3 years ago
Se lanza verticalmente una esfera con una rapidez de 30m/se. Determinar la rapidez de la esfera a una altura de 40m (g=10m/s2)
sergeinik [125]

v^2-{v_0}^2=2a(x-x_0)

dónde v es la velocidad de la esfera, v_0 es suya velocidad inicial, a=-g la aceleración debida a la gravedad, x la posición, y x_0 la posición inicial. Tomamos x_0=0\,\mathrm m a referirse a la posición de la esfera en el momento que la esfera fue lanzada.

Entonces

v^2-\left(30\,\dfrac{\mathrm m}{\mathrm s}\right)^2=2\left(-10\,\dfrac{\mathrm m}{\mathrm s^2}\right)(40\,\mathrm m)

\implies v^2=100\,\dfrac{\mathrm m^2}{\mathrm s^2}\implies v=\pm10\,\dfrac{\mathrm m}{\mathrm s}

Esto nos dice que la esfera alcanza una altura de 40 m en dos momentos - una vez hacia arriba y una vez hacia abajo. Sin embargo, independientemente del signo de la velocidad, sabemos que suya magnitud es 10 m/s, y así tenemos una rapidez de 10 m/s también en ambos momentos.

4 0
3 years ago
5 points
olga2289 [7]

Answer:

d. 5 ohms

Explanation:

For resistors in parallel, the equivalent resistance is found with:

1/Req = ∑(1/R)

1/R = 1/15 + 1/15 + 1/15

1/R = 3/15

R = 15/3

R = 5

8 0
3 years ago
A step-up transformer is connected to a generator that is delivering 141 V and 110 A. The ratio of the turns on the secondary to
hammer [34]

Answer:

31302 Volts and 55/111 Amps (≈0.5)

Explanation:

Secondary voltage / 141 = 1110 / 5

Secondary voltage = (1110*141) / 5

Secondary voltage = 31302

Amperage = 110/ (31302/141) = 55/111

5 0
3 years ago
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