Answer:
160 g
Explanation:
The formula for the calculation of moles is shown below:
For :-
Mass of = 196 g
Molar mass of = 98 g/mol
The formula for the calculation of moles is shown below:
Thus,
According to the given reaction:
1 mole of sulfuric acid reacts with 2 moles of NaOH
So,
2 moles of sulfuric acid reacts with 2*2 moles of NaOH
Moles of NaOH must react = 4 moles
Molar mass of NaOH = 40 g/mol
<u>Mass = Moles*molar mass = = 160 g</u>
The given question is incomplete. The complete question is :
Gaseous butane reacts with gaseous oxygen gas to produce gaseous carbon dioxide and gaseous water . If 1.31g of water is produced from the reaction of 4.65g of butane and 10.8g of oxygen gas, calculate the percent yield of water. Be sure your answer has the correct number of significant digits in it.
Answer: 28.0 %
Explanation:
To calculate the moles :
According to stoichiometry :
13 moles of require 2 moles of butane
Thus 0.34 moles of will require=
of butane
Thus is the limiting reagent as it limits the formation of product and butane is the excess reagent.
As 13 moles of give = 10 moles of
Thus 0.34 moles of give =
of
Mass of
The percent yield of water is 28.0 %