Answer:
3 2/3 units²
Step-by-step explanation:
Since the field is rectangular in nature;
Area of the field = Length * Width
Given
Length = 2 3/4
Width = 1 1/3
Area of the field = 2 3/4 * 1 1/3
Area of the field = 11/4 * 4/3
Area of the field = 4/4 * 11/3
Area of the field = 1 * 11/3
Area of the field = 11/3
Area of the field = 3 2/3
Hence the area of the field is 3 2/3 units²
Answer:
7i.
Step-by-step explanation:
Note : The given expression must be 
.
We have to write this radical value in the imaginary value.
The given value can be rewritten as
![[\because \sqrt{ab}=\sqrt{a}\sqrt{b}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Csqrt%7Bab%7D%3D%5Csqrt%7Ba%7D%5Csqrt%7Bb%7D%5D)
![[\because \sqrt{-1}=i]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Csqrt%7B-1%7D%3Di%5D)
Therefore, the required expression is 7i.
Answer:
you want us to do all that
Step-by-step explanation:
Answer:
Step-by-step explanation:don’t kno
Answer:
(0.5, 1.3)(0.5, 1.3)
Step-by-step explanation:
Given equations are:
As we can see that the given equations are linear equations which are graphed as straight lines on graph. The solution of two equations is the point of their intersection on the graph.
We can plot the graph of both equations using any online or desktop graphing tool.
We have used "Desmos" online graphing calculator to plot the graph of two lines (Picture Attached)
We can see from the graph that the lines intersect at: (0.517, 1.267)
Rounding off both coordinates of point of intersection to nearest tenth we get
(0.5, 1.3)
Hence,
(0.5, 1.3) is the correct answer
Keywords: Linear equations, variables
